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Define a Prolog predicate flatten(List, FlattenedList) that asserts List is any nested list of atoms and FlattenedList is the same list with the nesting removed. The atom [] should also be removed. Your predicate should only produce one answer. You may use the built-in predicates not, ! and append. Do not use a helper predicate.
?- flatten([a, [[b,c],d], [[e]], [f]], X).
X = [a,b,c,d,e,f] ;
no
?- flatten([a,[[]], [[c,d],e]], X).
X = [a,c,d,e] ;
Write a Program to illustrate the call by value? #include . int compute_sum(int m); int main( void) { int n=3, sum; printf("%d\n",n); /*3 is printed */ sum=compute_sum(n
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