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Define a function:
The radius of a circle is passed to the function to input argument rad; the function computes the area of this circle and stores it in the output argument area. In the function header, we have reserved word function, then an output argument area followed by an assignment operator =, then the name of the function (similar as the name of the M-file), and then the input argument rad, that is the radius. As there is an output argument in the function header, anywhere in the body of the function we should assign a value to this output argument. This is how the value is returned from a function. In this situation, the function is easy and all we have to do is assign to the output argument area the value of the built-in constant pi multiplied by the square of the input argument rad.
The function can be exhibited in the Command Window by using the type command.
>> type calcarea
function area = calcarea(rad)
% This computes the area of a circle
area = pi * rad * rad;
Hi, I need help with solving five-1st order ODE which are coupled. I need to plot these as well. Could I please get a quote. Thanks
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30 3/4- 15 5/6
Compute the result: To compute the area, the formula is required. In this situation, the area of the circle is π multiplied by the radius squared. Therefore, that means the va
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