Deadlock prevention, Operating System

Assignment Help:

While it is hard to resolve a deadlock which has been detected, fortunately it is fairly easy to prevent deadlocks from ever happening. The key is that the conditions above for deadlock are all necessary. We just have to ensure that at least one condition cannot be true. We de?nitely cannot get rid of the problem of ?nite resources; that is something we have to live with. And in many cases it can be dif?cult to get rid of the conditions of hold-and-wait and lack of preemption.

But we can eliminate circular waiting. One standard way of doing this is to have a so-called canonical ordering of the locks. This means that the programmer must always acquire the locks in a speci?ed order, such as ?rst lock1, then lock2, then lock3, etc. By doing so, we will ensure a system whose thread/resource graph is cycle-free, and therefore the system will be deadlock-free.


Related Discussions:- Deadlock prevention

Memory hierarchy, Difference between cache and associate memory

Difference between cache and associate memory

Define the client - server communications environment, Define the Client - ...

Define the Client - Server Communications Environment Today's client - server communications environment offers programmers great flexibility for application design. Applicatio

Why do systems store the operating system in firm ware, Q. Why do several s...

Q. Why do several systems store the operating system in firm ware and others on disk? Answer: For certain devices such like handheld PDAs and cellular telephones a disk with

What is low-level formatting, What is low-level formatting? Before a di...

What is low-level formatting? Before a disk can kept data, it must be required into sectors that the disk controller can read and write. This procedure is called low-level form

Memory organization and decoding, In a  p system each part (RAM, ROM, I/O) ...

In a  p system each part (RAM, ROM, I/O) has a unique set of numbers. The allocation of these numbers is usually stated in the form of a memory map. This is a plot of data bus agai

Read - write cycles of microprocessors, Examining the write/cycles as shown...

Examining the write/cycles as shown below We can see that the bus is designed for asynchronous read/write cycles. The operation of the write cycle is simple in that the add

THREADS, advantage and dis advantage of threads

advantage and dis advantage of threads

Explain advantages and inconveniences of ult, ADVANTAGES AND INCONVENIENCES...

ADVANTAGES AND INCONVENIENCES OF ULT Advantages: Thread switching doesn't involve the kernel - no mode switching Scheduling is able to be application specific -

Define the term system software, Question: (a) Define the term system ...

Question: (a) Define the term system software and application software, giving an example for each. (b) Draw a diagram to represent the abstract view of a computer system i

What is super block, What is super block A partition control block have...

What is super block A partition control block have partitions details, such as the number of blocks in the partition, size of the blocks, free-blocks and free-block pointers an

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd