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While it is hard to resolve a deadlock which has been detected, fortunately it is fairly easy to prevent deadlocks from ever happening. The key is that the conditions above for deadlock are all necessary. We just have to ensure that at least one condition cannot be true. We de?nitely cannot get rid of the problem of ?nite resources; that is something we have to live with. And in many cases it can be dif?cult to get rid of the conditions of hold-and-wait and lack of preemption.
But we can eliminate circular waiting. One standard way of doing this is to have a so-called canonical ordering of the locks. This means that the programmer must always acquire the locks in a speci?ed order, such as ?rst lock1, then lock2, then lock3, etc. By doing so, we will ensure a system whose thread/resource graph is cycle-free, and therefore the system will be deadlock-free.
What are the different files attributes? File name:-it's the name of the file. It's the name with which the user identifies. Identifiers:-it's created when a file is created
how is it possible
What is a two state process model? At any time a process is being implementing by a processor or not. Therefore a process may be in Running or not running state. When an Ope
Hashed page table method A general approach for managing address spaces larger than 32 bits is to use a hashed page table with the hash values being the virtual-page number.
What are a safe state and an unsafe state? Answer: A state is safe if the system can allocate resources to every process in some order and still avoid a deadlock. A system is
A Unix shell is a shell or command-line interpreter that gives a traditional user interface for the Unix-likesystems and for Unix operating system. Users operates the operation of
Question 1: a) Distinguish between "Long-Term Scheduler" and "Short-Term Scheduler". b) Describe the benefits of "Threads". c) Name three types of CPU Scheduling. Que
Explain Wait for Graph a. Use a resource allocation graph to derive a wait-for graph. b. Wait-for graph acquired by making an edge from p 1 to p 2 iff p 1 is waiting for
Q. The instance of handshaking used 2 bits: a busy bit as well as a command-ready bit. Is it probable to implement this handshaking with only 1 bit? If it is illustrate the protoc
Deadlock Detection and Recovery It's a method of permitting the system to enter a deadlock state, detect it and then recover. Deadlock detection : Is the process of
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