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While it is hard to resolve a deadlock which has been detected, fortunately it is fairly easy to prevent deadlocks from ever happening. The key is that the conditions above for deadlock are all necessary. We just have to ensure that at least one condition cannot be true. We de?nitely cannot get rid of the problem of ?nite resources; that is something we have to live with. And in many cases it can be dif?cult to get rid of the conditions of hold-and-wait and lack of preemption.
But we can eliminate circular waiting. One standard way of doing this is to have a so-called canonical ordering of the locks. This means that the programmer must always acquire the locks in a speci?ed order, such as ?rst lock1, then lock2, then lock3, etc. By doing so, we will ensure a system whose thread/resource graph is cycle-free, and therefore the system will be deadlock-free.
Q. What are the three main activities of an operating system in regard to secondary-storage management? Answer: 1) Free-space management 2) Storage allocation 3) Disk
Problem: a) Prepare a short note on the standard Linux File System. b) Prepare a short note on the RPM Package Management Tool. c) Briefly explain the two types of login
what is dual mode operation
why we say" OS is a resource allocator" and “OS is a control program"?
Enhanced Second chance algorithm In this a modify bit is as well used. Now if the ordered pair of reference and modify is (0,0) neither recently used nor modified - the best
A paper mill produces two grades of paper viz., X and Y. Because of raw material restrictions, it cannot produce more than 400 tons of grade X paper and 300 tons of grade Y paper i
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To explore the UNIX file system, use basic UNIX commands and use a text editor. Task: 1. Logon to Linux. 2. Create a directory "Unix" under your home d
Virtual file systems The file-system execution having of three major layers. The first layer is the file-system interface, based on the open, read, write and close calls and fi
MEMORY MANAGEMENT USING BIT MAPS In this memory is separated into different allocation units each of some particular size(a few bites).consider every space of size 4k. A
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