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While it is hard to resolve a deadlock which has been detected, fortunately it is fairly easy to prevent deadlocks from ever happening. The key is that the conditions above for deadlock are all necessary. We just have to ensure that at least one condition cannot be true. We de?nitely cannot get rid of the problem of ?nite resources; that is something we have to live with. And in many cases it can be dif?cult to get rid of the conditions of hold-and-wait and lack of preemption.
But we can eliminate circular waiting. One standard way of doing this is to have a so-called canonical ordering of the locks. This means that the programmer must always acquire the locks in a speci?ed order, such as ?rst lock1, then lock2, then lock3, etc. By doing so, we will ensure a system whose thread/resource graph is cycle-free, and therefore the system will be deadlock-free.
Assume that P A , P B and P C are three distinguished program s . When P A is executed, it needs 10 ticks to complete its execution and it forks new processes executing P B at tick
1. What must a kernel provide for an effective user-level thread implementation? 2. With respect to the quantum q in a scheduling algorithm, explain and discuss the impact of th
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Parent process P creates three child processes, C1, C2, and C3. Each child process executes a memory and CPU intensive application of your choice. Your choice should be such that
Now let's implement bounded producer-consumer with semaphores, a Coke machine which is initially empty: semaphore sem_mutex = 1 // binary semaphore for mutual exclusion, 1==unlo
Is disk scheduling, other than FCFS scheduling, useful in a single-user environment? Explain your answer. In a single-user environment, the I/O queue usually is blank. Requests
Question 1: a) Distinguish between "Long-Term Scheduler" and "Short-Term Scheduler". b) Describe the benefits of "Threads". c) Name three types of CPU Scheduling. Que
Convert the following from hex to binary and draw it on the memory map. RAM = 0000 -> 00FF EPROM = FF00 -> FFFF Answer: 0000 0000 0000 0000 (0) RAM sta
LINUX VS WINDOWS I/O MANAGEMENT
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