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i) Calculate the eigenvalues of a 100 hp, 1150 rpm dc machine at rated flux with no extra load inertia. Use the "hot" value of the armature resistance. Calculate estimates of the resulting speed overshoot and settling time (within 2%) for a step armature voltage input, beginning at an initial current of 0.
ii) Now assume that a closed-loop current regulator is introduced as shown in Fig. 2.7-3 of the book. What are the new eigenvalues of the motor-plus-regulator system if the current regulator gain Ki is set to 10? Ignore the mechanical damping constant (B=0) in Fig. 2.7-3. Calculate estimates of the resulting overshoot and settling time for a step current input, beginning at an initial current of 0.
iii) Now consider a closed-loop speed control system as shown in Fig. 2.7-5. Assume that the current regulator dynamics are very fast compared to the outer speed loop and the current regulator gain is high enough so that it is effectively "ideal". Calculate the eigenvalue of this closed-loop system for Kp=100, τz=∞. (Assume B=D=0 again.) Calculate the resulting output speed overshoot and approximate settling time of the closed-loop system for a step speed command input.
Q. What do you mean by Oscilloscope? To measure time-varying signals (voltages and currents), an instrument known as an oscilloscope is employed. It can be used as a practical
Q. A 5-kVA, 480:120-V, two-winding, 60-Hz, single-phase transformer has an efficiency of 95% while delivering rated load at rated voltage and 0.8 power factor lagging. This transfo
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What is resistivity? Resistivity of a material may be explained as the resistance of the material having unit length and also unit cross sectional area. Unit of it is ohm-m.
What is the main function of the slip ring
how to derive its transfer function
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Three transformers are provided with the following rating values: 1) 2400/240 V, 55kVA, Req1 = (0.1 + 0.0Y) Ohm and Xeq1 = (0.15 + 0.XX) Ohm. 2) 240/120 V, 25kVA, Req1 = (0.1
Crossovers are generally used with loudspeakers having multiple drivers. Loudspeakers with single drivers are unable to cover the entire frequency range i.e from low to high freque
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