Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
D.C. Generator
A magnetic field is produced by afield coil supplied with a D.C. current and a rotor is placed between shaped pole pieces and wound with an armature winding. The diagram above shows only one turn of the armature winding, but in practice there will usually be more than one. The ends of the armature winding are connected to two slip rings that rotate with the armature and the voltage generated is 'picked off' the rings by brushes that bear against the slip rings
The emf generated may be calculated either using the equation for the emf induced in a conductor of length l moving
in an electric field of flux density B webers/m 2
e=B.l.v
with a velocity v m/sec or by considering the rate of change of flux linkage with the armature coil. We shall use the latter method. Due to the shaping of the pole pieces, the flux threading through a particular armature coil is constant at + max as it turns from O4 to O1 and decreases linearly from +Ømax to -Ømin while the rotor is turning from O1 to O2 . It is constant again during O2 to O3 and then increases linearly during O3to O4. (ref graph)
10. List the three ways in which an RTOS handles ISRs in a multitasking environment
1. In the circuit shown below, the capacitor initially has a voltage across it 4 Volts (at t = 0). a. Write down the expression for V C (t) when the switch is closed. b. Wr
STC Set Carry Instruction This instruction sets the carry flag to 1. The instruction format is STC Flags except carry no other flags are affected
Explain the TEST instruction. TEST: The TEST instruction executes the AND operation. The difference is as the AND instruction changes the destination operand, whereas the TEST
Q. At the two terminals (A, B) of a one-port network, the voltage and the current are given to be v(t) =200 √2 cos (377t + 60°) V and i(t) = 10√2 cos(377t + 30°) A. (a) Determin
Q. Obtain the Thévenin and Norton equivalent circuits for the portion of the circuit to the left of terminals a-b in Figure, and find the current in the 200- resistance.
We have seen that a practical power source may be modelled by an ideal constant voltage source in series with a resistor - a Thevenin equivalent circuit Alternati
PRINCIPLE OF LED
Charge density In a semiconductor
block diagram of digital control system and explain each block
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd