Crystal field splitting in octahedral complexes, Chemistry

Assignment Help:

Q. Crystal Field Splitting in Octahedral Complexes?

Let us consider an octahedral complex, ML6, where M is a metal ion and L stands for a ligand. The total charge on the complex and the oxidation state of the metal ion are omitted since they would not make any difference in our result. The complex can be represented as shown in Fig.

2398_Crystal Field Splitting in Octahedral Complexes.png


Related Discussions:- Crystal field splitting in octahedral complexes

What is pairing energy explain, Q. What is Pairing energy explain? Pair...

Q. What is Pairing energy explain? Pairing energy, P, depends mainly on the electronic distribution of the central metal ion and its value can be obtained from the atomic spect

Halides, The elements of this group form a number of compounds with halogen...

The elements of this group form a number of compounds with halogens. The halogen compounds of S. Se, Te and Po are called as halides. For oxygen, only the fluoro compounds

Sublimation, How can sublimation be useful? Ex. It can be used by ... ...

How can sublimation be useful? Ex. It can be used by ... to...

When an electron jumps from l to k shell, When an electron jumps from L  ...

When an electron jumps from L  to K  shell: (1) Energy is absorbed   (2) Energy is released  (3) Energy is sometimes absorbed and sometimes  released (4) Energy is nei

Solid nacl is a bad conductor of electricity, Solid Nacl is a bad conductor...

Solid Nacl is a bad conductor of electricity since: (1) In solid  Nacl  there are no ions (2) Nacl    Solid   is covalent (3) In solid  Nacl  there is no motion of ions

Hund''s rule which element contains six unpaired electron, Following Hund's...

Following Hund's rule which element contains six unpaired electron: (1) Fe     (2) Co       (3) Ni    (4) Cr Ans: Cr

Explain the un-ionized form of vanillin, Explain the un-ionized form of van...

Explain the un-ionized form of vanillin It is the un-ionized form of vanillin that has the typical odor.  In NaOH solution, the phenol group ofvanillin ionizes to its conjugate

Acid radical., tests for mixture of acid radicals

tests for mixture of acid radicals

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd