Cross product - vector, Mathematics

Assignment Help:

Cross Product

In this last section we will look at the cross product of two vectors.  We must note that the cross product needs both of the vectors to be three dimensional (3D) vectors.  

 As well, before getting into how to calculate these we should point out a major variation in between dot products and cross products. The product of a dot product is a number and the result of a cross product is a vector!  Be cautious not to confuse the two.

Thus, let's begin with the two vectors a = (a1, a2, a3) illustrated by the formula, and b = (b1, b2 , b3) then the cross product is illustrated by formula

a * b = (a2b3 - a3b2, a3b1 - a1b3, a1b2 - a2b1)

This is not a simple formula to remember.  There are two methods to derive this formula.  Both of them make use of the fact that the cross product is actually the determinant of a 3x3 matrix.  If you don't be familiar with what this is that is don't worry about it.  You don't require to know anything about matrices or determinants to make use of either of the methods.  The notation for the determinant is like this,

473_Cross Product - Vector 3.png

The first row in the above determinant is the standard basis vectors and should appear in the order given here.  The 2nd row is the components of a? and the third row is the components of b.  Now, let's take a look at the dissimilar methods for getting the formula.

 The first technique uses the Method of Cofactors.  If you do not know the method or technique of cofactors that is fine, the result is all that we want.  Formula is given below:

103_Cross Product - Vector 2.png

This formula is not as hard to remember as it might at first come out to be.  First, the terms change in sign and notice that the 2x2 is missing the column below the standard basis vector that multiplies it also the row of standard basis vectors.

The second method is little easier; though, many textbooks don't cover this method as it will only work on 3x3 determinants.  This technique says to take the determinant as listed above and after that copy the first two columns onto the end as displayed below.

2002_Cross Product - Vector 1.png

We now have three diagonals which move from left to right and three diagonals which move from right to left.  We multiply all along each diagonal and add those that move from left to right and subtract those which move from right to left.


Related Discussions:- Cross product - vector

Obtain the number of significant modes, On the Assessment page for the modu...

On the Assessment page for the module Moodle site you will find five frequency response functions for the frequency range 20 to 100 Hz in the EXCEL spreadsheet "FRF_Data". These a

Mod(z-25i)<15, Mod(Z-25i)   Sol) mod (Z-25i) means Z lies in the circumfer...

Mod(Z-25i)   Sol) mod (Z-25i) means Z lies in the circumference of the circle with (0,25) at its centre and radius less then 15. so difference in the max and min value of arg Z is

Logarithmic functions, If x = b y where both b > 0, x > 0, then we d...

If x = b y where both b > 0, x > 0, then we define y = log b x, which is read as "y is the log to the base b of x". This means that, log b x or y is the number to

Solid, The lateral edge of a pyramidal church spire is 61feet.Each side of ...

The lateral edge of a pyramidal church spire is 61feet.Each side of its octagonal base is 22feet. What will be the cost of painting the spire at 2.5 cents a square foot

Determine matrix of transformation for orthogonal projection, Determine the...

Determine the matrix of transformation for the orthogonal projection onto the line L that passes through the origin and is in the direction Û=(3/13 , 4/13 , 12/13). Determine the r

Position vector - calculus, Position Vector There is one presentation o...

Position Vector There is one presentation of a vector that is unique in some way.  The presentation of the ¯v = (a 1 ,a 2 ,a 3 ) that begins at the point  A = (0,0,0) and ends

Find and classify all the equilibrium solutions, Find and classify all the ...

Find and classify all the equilibrium solutions to the subsequent differential equation. y' = y 2 - y - 6 Solution First, get the equilibrium solutions. It is generally

VECTOR, the sum of the vector QR, -SR, TQ and 2ST is?

the sum of the vector QR, -SR, TQ and 2ST is?

Proof of the derivative of a constant, Proof of the Derivative of a Constan...

Proof of the Derivative of a Constant : d(c)/dx = 0 It is very easy to prove by using the definition of the derivative therefore define, f(x) = c and the utilize the definiti

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd