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Sir, With due respect,I, beg to state that I want to join as a maths expert and earn some money. I would be grateful to you if you guide me in this regard.
∫1/sin2x dx = ∫cosec2x dx = 1/2 log[cosec2x - cot2x] + c = 1/2 log[tan x] + c Detailed derivation of ∫cosec x dx = ∫cosec x(cosec x - cot x)/(cosec x - cot x) dx = ∫(cosec 2 x
How would you solve this question? 4/5 = 8/x+2
one half y minus 14
If the points for a right angle triangle are XYZ where do I mark the points?
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