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Correct statement is:
(1) K=4s1, Cr= 3d4 4s2, Cu= 3d10 4s2
(2) K=4s2, Cr= 3d4 4s2, Cu= 3d10 4s2
(3) K=4s2 Cr= 3d5 4s1, Cu= 3d10 4s2
(4) K=4s1, Cr= 3d5 4s1, Cu= 3d10 4s1
Ans: K=4s1, Cr= 3d5 4s1, Cu= 3d10 4s1
Why can classical (Werner) octaedral complexes with no pi-bonding have between 12-22 valence electrons, whereas octahedral complexes with pi-bonding must have 18 electrons?
1.sheilding & de-sheilding 2.magnetic anisotropy 3.hydrogen bonding
how is it solved?????????
list the advantage and disadvantage teaching methods in chemistry
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the method used for concentration of tin stone is
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