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Convert the following from hex to binary and draw it on the memory map.
RAM = 0000 -> 00FF EPROM = FF00 -> FFFF
Answer:
0000 0000 0000 0000 (0) RAM start
0000 0000 1111 1111 (255 byte) RAM stop
1111 1111 0000 0000 (63.75K) Eprom start
1111 1111 1111 1111 (64K) Eprom stop The memory map is shown below:-
Due to the tri-state nature of the I.C's (Ram, Rom etc.) they may be placed in parallel and 'turned on ' when they are required. This process is termed decoding. There are two types of decoding:- 1. Partial decoding 2. Absolute decoding
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A- Consider a computer system that provides a virtual memory space that consists of 8 pages. The physical memory contains 4 pages where the page size is 4Kbytes. Assume that at sp
GUI - Short for Graphical User Interface a GUI Operating System contains icons and graphics and is commonly navigated by using a computer mouse. Below are some instances of GUI Op
Second chance Algorithm When the page is chosen the reference bit is checked to see whether it has been referenced before. If that is the case after that it is given a second c
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Central to implementation of a modern memory management system is the page replacement algorithm. Modern virtual memory systems break memory up into pages and map (via a page table
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