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Convert the following from hex to binary and draw it on the memory map.
RAM = 0000 -> 00FF EPROM = FF00 -> FFFF
Answer:
0000 0000 0000 0000 (0) RAM start
0000 0000 1111 1111 (255 byte) RAM stop
1111 1111 0000 0000 (63.75K) Eprom start
1111 1111 1111 1111 (64K) Eprom stop The memory map is shown below:-
Due to the tri-state nature of the I.C's (Ram, Rom etc.) they may be placed in parallel and 'turned on ' when they are required. This process is termed decoding. There are two types of decoding:- 1. Partial decoding 2. Absolute decoding
write a linux command to display lines from 25 - 45 of directory "/edc/password" write a linux command to display directory in /edc
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demonstrate ergonomics
Q. Explain a mechanism by which one segment could belong to the address space of two different processes. Answer: Because segment tables are a collection of base-limit register
i need the job to be done within 3 days
Q. Why is it complicated to protect a system in which users are allowed to do their own I/O? Answer: In earlier chapters we identified a distinction among kernel and user mod
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What is the main advantage of the layered approach to system design? As in all cases of modular design, designing an operating system in a modular way has several benefits. Th
How can the deadlock be prevented Bankers algorithm : The Resource allocation graph algorithm isn't applicable to a resource allocation system with multiple instances of every
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