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Convert the following from hex to binary and draw it on the memory map.
RAM = 0000 -> 00FF EPROM = FF00 -> FFFF
Answer:
0000 0000 0000 0000 (0) RAM start
0000 0000 1111 1111 (255 byte) RAM stop
1111 1111 0000 0000 (63.75K) Eprom start
1111 1111 1111 1111 (64K) Eprom stop The memory map is shown below:-
Due to the tri-state nature of the I.C's (Ram, Rom etc.) they may be placed in parallel and 'turned on ' when they are required. This process is termed decoding. There are two types of decoding:- 1. Partial decoding 2. Absolute decoding
Determine how Action implementing instruction’s meaning are a actually carried out Action implementing meaning of instruction are a actually carried out Instruction executio
Produce a referenced four page report which describes the possible functionality of the system; similar systems that are out there and different possible approaches to delivering t
Multi-level page tables are tree-like structures to hold page tables. As an example, consider a two- level page table, again on a 32-bit architecture with 212 = 4 kbyte pages. Now,
server configure
Q. You have devised a fresh page-replacement algorithm that you think may be optimal. In a few contorted test cases Belady's anomaly occurs. Is the fresh algorithm optimal? Descr
Deadlocks can be detected while the program is running, by running cycle detection algorithms on the graph that de?nes the current use of resources. De?ne this graph as follows:
what is the need-to-know principle? why is it important for a protection system to adhere to this principle?
Q. Regard as a logical address space of eight pages of 1024 words every mapped onto a physical memory of 32 frames. a. How several bits are there in the logical address? b. H
The idea of reference counting is to maintain, for every object, the total number of references to that object, i.e. the number of "incoming" pointers. Whenever the number of refer
Virtual addresses are made up of two parts: the ?rst part is the page number, and the second part is an offset inside that page. Suppose our pages are 4kb (4096 = 212 bytes) long,
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