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Convert the following from hex to binary and draw it on the memory map.
RAM = 0000 -> 00FF EPROM = FF00 -> FFFF
Answer:
0000 0000 0000 0000 (0) RAM start
0000 0000 1111 1111 (255 byte) RAM stop
1111 1111 0000 0000 (63.75K) Eprom start
1111 1111 1111 1111 (64K) Eprom stop The memory map is shown below:-
Due to the tri-state nature of the I.C's (Ram, Rom etc.) they may be placed in parallel and 'turned on ' when they are required. This process is termed decoding. There are two types of decoding:- 1. Partial decoding 2. Absolute decoding
Questiion 1 Use Priority Scheduling Algorithm to schedule the following processes Process Burst Time Priority/Time P1
Define the Non Monolithic Coding First off, client - server developers must adopt a new programming mindset. Much as with the shift to object - oriented design, developers sho
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A hard-disk drive reads “120 GB HDD 7200 rpm 3 GB/sec transfer rate”. If the drive has a sector size of 512 bytes, what is the average rotational latency and transfer time to read
What do you mean by semaphore? Semaphore : A synchronization variable that acquires on positive integer values. Invented by the Dijkstra P (semaphore): an atomic proce
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Briefly explain about file system implementation? Several on-disk and in-memory structures are used to execute a file system. On disk, the file system may have information abou
Compare contiguous-memory allocation with pure paging in the following aspects: 1. In support of dynamic memory allocation: most systems allow programs to allocate more memory t
What are the deadlock p revention methodologies? a. Necessitate that processes request all resources before starting - if cannot be granted don't run. b. Process
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