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Convert the following from hex to binary and draw it on the memory map.
RAM = 0000 -> 00FF EPROM = FF00 -> FFFF
Answer:
0000 0000 0000 0000 (0) RAM start
0000 0000 1111 1111 (255 byte) RAM stop
1111 1111 0000 0000 (63.75K) Eprom start
1111 1111 1111 1111 (64K) Eprom stop The memory map is shown below:-
Due to the tri-state nature of the I.C's (Ram, Rom etc.) they may be placed in parallel and 'turned on ' when they are required. This process is termed decoding. There are two types of decoding:- 1. Partial decoding 2. Absolute decoding
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What are the deadlock p revention methodologies? a. Necessitate that processes request all resources before starting - if cannot be granted don't run. b. Process
Q. Why is rotational latency typically not considered in disk scheduling? How would you alter SSTF, SCAN and C-SCAN to comprise latency optimization? Answer: Most disks don't
define pipe
One reason to learn C and C++ is simply that so much software is written in these languages. A related, butmore fundamental reason, is that C and C++ are relatively low-level, allo
how do semaphores help us in eliminating deadlock conditions?
What advantages are there to this two-level directory? Users are isolated from each other. Users have more freedom in choosing file names.
Briefly discuss on real-time scheduling? It is divided into two types. Hard real-time systems are needed to complete a critical task within a guaranteed amount of time. T
Define I/O and CPU Bursts Applications typically to through cycle of CPU bursts and Input/output bursts. Since the CPU sits idle during I/O operations, efficiency is improved
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