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Convert the following from hex to binary and draw it on the memory map.
RAM = 0000 -> 00FF EPROM = FF00 -> FFFF
Answer:
0000 0000 0000 0000 (0) RAM start
0000 0000 1111 1111 (255 byte) RAM stop
1111 1111 0000 0000 (63.75K) Eprom start
1111 1111 1111 1111 (64K) Eprom stop The memory map is shown below:-
Due to the tri-state nature of the I.C's (Ram, Rom etc.) they may be placed in parallel and 'turned on ' when they are required. This process is termed decoding. There are two types of decoding:- 1. Partial decoding 2. Absolute decoding
Q. Why do several systems store the operating system in firm ware and others on disk? Answer: For certain devices such like handheld PDAs and cellular telephones a disk with
Long term scheduler calculates which processes are admitted to the machine for processing. It accepts the degree of multiprogramming. Once accepted, a job converts a process.
Is it probable to have a deadlock involving only one single process? Describe your answer. Answer: No This pursue directly from the hold-and-wait condition.
What is meant by context switch? Switching the CPU to another process needs saving the state of the old process and loading the saved state for the latest process. This task is
what is system performence?
BEST FIT ALGORITHM Here scanning is for the finest fit one. Signifies it searches the entire list for the best fit position. For the process therefore in that the process will
What is the essence of facility location in production operation management
Describe the differences among short-term, medium-term, and long-term scheduling. Short-term (CPU scheduler)-selects from jobs in memory those jobs that are ready to execu
Q. What system calls have to be implementing by a command interpreter or shell in order to start a new process? Answer: In the UNIX systems a fork system call followed by an ex
SSTF (Shortest Seek Time First) After a demand go to the closest request in the work queue regardless of direction Decrease total seek time compared to FCFS Disadv
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