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Convert the following from hex to binary and draw it on the memory map.
RAM = 0000 -> 00FF EPROM = FF00 -> FFFF
Answer:
0000 0000 0000 0000 (0) RAM start
0000 0000 1111 1111 (255 byte) RAM stop
1111 1111 0000 0000 (63.75K) Eprom start
1111 1111 1111 1111 (64K) Eprom stop The memory map is shown below:-
Due to the tri-state nature of the I.C's (Ram, Rom etc.) they may be placed in parallel and 'turned on ' when they are required. This process is termed decoding. There are two types of decoding:- 1. Partial decoding 2. Absolute decoding
what if we need the portion from a text based on some keyword. For eg. My file is like below, ------------------------------------------------ Order=[ 1 2 3 4 5 Order=[ 6 7 8 9
Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4
When a program issues a memory load or store operation, the virtual addresses (VAs) used in those operations have to be translated into "real" physical memory addresses (PAs). This
Q. Consider the following page-replacement algorithms. Rank the algorithms on a five-point scale from "bad" to "perfect" according to their page-fault rate. Detach those algorithm
KERNEL ACTIVITY FOR ULTS: The kernel isn't aware of thread activity but it is still managing process activity. When a thread compose a system call the whole process will be bl
Q. What are the three main activities of an operating system in regard to memory management? Answer: a. Keep follows of which parts of memory are currently being used and
What is internal fragmentation? Consider holes of 20k assume the process requests 18 bites. If we allocate accurately the request block, we are left with a hole of 2k. The over
RESOURCE ALLOCATION GRAPH When a process Pi wishes an instance of resource type Rj, a request edge is inserted in the resource allocation graph. When this request is able to be
Define where a Program generation activity aims Program generation activity aims at Automatic generation of program
Direct communication With direct communication each process that requires to communicate must explicitly name the recipient or sender of the communication. The send and receive
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