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Convert the following from hex to binary and draw it on the memory map.
RAM = 0000 -> 00FF EPROM = FF00 -> FFFF
Answer:
0000 0000 0000 0000 (0) RAM start
0000 0000 1111 1111 (255 byte) RAM stop
1111 1111 0000 0000 (63.75K) Eprom start
1111 1111 1111 1111 (64K) Eprom stop The memory map is shown below:-
Due to the tri-state nature of the I.C's (Ram, Rom etc.) they may be placed in parallel and 'turned on ' when they are required. This process is termed decoding. There are two types of decoding:- 1. Partial decoding 2. Absolute decoding
Clocks in distributed systems : a. Why are clocks difficult to synchronize in distributed systems? b. What features in a system assume that the clocks are (reasonably) synchr
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Normal 0 false false false EN-IN X-NONE X-NONE MicrosoftInternetExplorer4
Question: A set of processes are in a deadlock state when every process in the set is waiting for an event that can be caused by only another process in the set. (a) There
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Explain the concept of Reentrancy? It is a useful, memory-saving method for multiprogrammed timesharing systems. A Reentrant Procedure is one in which many users can share a si
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