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Convert coordinate:
class rect{
private :
float x,y;
public :
void input()
{
cout <<"enter rect coords\n";
cin >> x>> y>>"\n";
}
void output()
cout << x<<"\n" << y;
rect ()//dummy consructor
rect (float a,float b)//constructor
x=a;
y=b;
}; //end of class
class polar {
float r,q;
cout <<"enter polar coords\n";
cin>>r>>q;
cout << r< } operator rect(); };//end of class polar :: operator rect() { float a=r*cos(22*q/(7*180)); float b=r*sin(22*q/(7*180)); return rect(a,b);//calling constructor inbuild that it will //return rect type } void main() { rect a; polar p; clrscr(); p.input(); a=p; a.output(); getch(); }
} operator rect(); };//end of class polar :: operator rect() { float a=r*cos(22*q/(7*180)); float b=r*sin(22*q/(7*180)); return rect(a,b);//calling constructor inbuild that it will //return rect type } void main() { rect a; polar p; clrscr(); p.input(); a=p; a.output(); getch(); }
operator rect();
};//end of class
polar :: operator rect()
float a=r*cos(22*q/(7*180));
float b=r*sin(22*q/(7*180));
return rect(a,b);//calling constructor inbuild that it will
//return rect type
void main()
rect a;
polar p;
clrscr();
p.input();
a=p;
a.output();
getch();
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what is a variable
b) Why copy constructor accepts reference to an object and not the object itself? What happens if we do otherwise?
Dynamic Initialization of objects: It is initializing the objects by passing the valued to the constructor from the user input or other means. Through cin operator a value
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