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Suppose G = (N, Σ, P, S) is a reduced grammar (we can certainly reduce G if we haven't already). Our algorithm is as follows:
1. Define maxrhs(G) to be the maximum length of the right hand side of any production.
2. While maxrhs 3 we convert G to an equivalent reduced grammar G' with smaller maxrhs.
3. a) Choose a production A → α where is of maximal length in G.
b) Rewrite α as α1α2 where |α1| = |α1|/2 (largest integer ≤ |α1|/2) and |α2| = |α2|/2 (smallest integer ≥ |α2|/2)
c) Replace A -> α in P by A -> α1B and B -> α2
If we repeat step 3 for all productions of maximal length we create a grammar G' all of whose productions are of smaller length than maxrhs.
We can then apply the algorithm to G' and continue until we reach a grammar that has maxrhs ≤ 2.
constract context free g ={ a^n b^m : m,n >=0 and n
proof ogdens lemma .with example i am not able to undestand the meaning of distinguished position .
Design a turing machine to compute x + y (x,y > 0) with x an y in unary, seperated by a # (descrition and genereal idea is needed ... no need for all TM moves)
dfa for (00)*(11)*
One might assume that non-closure under concatenation would imply non closure under both Kleene- and positive closure, since the concatenation of a language with itself is included
program in C++ of Arden''s Theorem
let G=(V,T,S,P) where V={a,b,A,B,S}, T={a,b},S the start symbol and P={S->Aba, A->BB, B->ab,AB->b} 1.show the derivation sentence for the string ababba 2. find a sentential form
What are codds rule
The initial ID of the automaton given in Figure 3, running on input ‘aabbba' is (A, aabbba) The ID after the ?rst three transitions of the computation is (F, bba) The p
explain turing machine .
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