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Suppose G = (N, Σ, P, S) is a reduced grammar (we can certainly reduce G if we haven't already). Our algorithm is as follows:
1. Define maxrhs(G) to be the maximum length of the right hand side of any production.
2. While maxrhs 3 we convert G to an equivalent reduced grammar G' with smaller maxrhs.
3. a) Choose a production A → α where is of maximal length in G.
b) Rewrite α as α1α2 where |α1| = |α1|/2 (largest integer ≤ |α1|/2) and |α2| = |α2|/2 (smallest integer ≥ |α2|/2)
c) Replace A -> α in P by A -> α1B and B -> α2
If we repeat step 3 for all productions of maximal length we create a grammar G' all of whose productions are of smaller length than maxrhs.
We can then apply the algorithm to G' and continue until we reach a grammar that has maxrhs ≤ 2.
The fact that regular languages are closed under Boolean operations simpli?es the process of establishing regularity of languages; in essence we can augment the regular operations
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As de?ned the powerset construction builds a DFA with many states that can never be reached from Q′ 0 . Since they cannot be reached from Q′ 0 there is no path from Q′ 0 to a sta
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One of the first issues to resolve, when exploring any mechanism for defining languages is the question of how to go about constructing instances of the mechanism which define part
The Emptiness Problem is the problem of deciding if a given regular language is empty (= ∅). Theorem 4 (Emptiness) The Emptiness Problem for Regular Languages is decidable. P
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