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Assume that (xn) is a sequence of real numbers and that a, b € R with a is not eaqual to 0.
(a) If (xn) converges to x, show that (|axn + b|) converges to |ax + b|.(b) Give an instance , with brief justi cation, where (|xn|) converges but (xn) does not.(c) If (|xn|) converges to 0, elustratethat (xn) converges to 0.
In (a) you need to use only the de nition of convergence and no other limit theorems.
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( 1/2)2 x 1/5+1/6=
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Let u = sin(x). Then du = cos(x) dx. So you can now antidifferentiate e^u du. This is e^u + C = e^sin(x) + C. Then substitute your range 0 to pi. e^sin (pi)-e^sin(0) =0-0 =0
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