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Control Transfer or Branching Instruction
Control transfer instructions transfer the flow of execution of the program to a new address specified in the instruction indirectly or directly. When these types of instructions are executed, the CS register and IP registers get loaded with new values of CS and IP register equivalent to the location where the flow of execution is going to be transferred. Depending on the addressing modes, the CS register may/ may not be modified. These instructions are classified in 2 types:
1) Unconditional Control Transfer (Branch) Instructions:- In this case, the execution control is transferred to the specified location independent of any condition or status. The CS and IP register are unconditionally modified to the new CS and IP register.
2) Conditional Control Transfer (Branch) Instruction:- In this, the control is transferred to the specified location provided the result of the past operation satisfies a specific condition, or else, the execution continues in normal flow sequence. Condition code flags replicate the results of the past operations. In other term, by using this type of instruction the control will be transferred to specific specified location, if a specific flag satisfies the condition.
init_lcd ;(this initialises a 2 row lcd) bcf TRISA,0 ;PORTA bit 0 as an output (lcd RS pin) bcf TRISA,1 ;PORTA bit 1
CMPS : Compare String Byte or String Word:-The CMPS instruction may be utilized to compare two strings of Words or byte. The length of the string ought to be stored in the CX. If
from pin description it seems that 8086 has 16 address/data lines i.e.AD0_AD15.The physical address is however is larger than 2^16.How this condition can be handled
Open notepad and enter the code for a program that calculates the following arithmetic expression: x = a + b + c - d - e + f The operands a, b, c, d, e, f, and x should be declared
Develop an assembly language program for the system and simulate it using MPLAB. From this produce a demo program (in Assembly language) that will run on the MatrixMultimedia Devel
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Example : Add the contents of the 2000H: 0500H memory location to contents of 3000H: 0600H and store the result in 5000H: 0700H. Solution : Unlike the past example progra
which uses BIOS interrupt INT 21 to read current system time and displays it on the top-left corner of screen.
AAD stand for what??
Description: LC3 allows input from keyboard and output to display on the screen. This lab will exercise the input/output capability using LC-3 Assembly language. Procedure
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