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If r per annum is the rate at which the principal A is compounded annually, then at the end of k years, the money due is
Q = A (1 + r)k
Suppose compounding is done continuously. i.e. at every instant the principal A is compounded at R per annum. Then,
Q = A eRk
The relationship between R and r is given by the following reasoning:
A (1 + r)k = A eRk
Example
If R = 5.25%, then ln(1 + r) = 5.25% or r = 5.39%
Suppose Rs.100 is being compounded annually at the rate of 10% per annum. What is the future value of Rs.100 at the end of the third year? What is the effective continuously compounded rate of interest? What is the future value of Rs.100 at the end of the third year, using this interest rate?
FV(Rs.100) = 100 x (1.10)3 = 133.1
If r = 0.1, then the continuously compounded rate of interest R is given by
R = ln(1 + 0.1) = 0.0953
FV(Rs.100) = 100 e0.0953 x 3 = 100 x 1.331 = 133.1
If OA = OB = 14cm, ∠AOB=90 o , find the area of shaded region. (Ans:21cm 2 ) Ans: Area of the shaded region = Area of ? AOB - Area of Semi Circle = 1/2 x 14 x
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15 is 30% of what number?
what are these all about and could i have some examples of them please
The Ravens played 25 home games this year. They had 9 losses and 2 ties. How many games did they win? Eleven games are accounted for along with the losses and ties (9 + 2 = 11)
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my daughter brought home home work im not sure how to do it the fractions has to be labled from least to greatest
Position Vector There is one presentation of a vector that is unique in some way. The presentation of the ¯v = (a 1 ,a 2 ,a 3 ) that begins at the point A = (0,0,0) and ends
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