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Define Constant argument:
The argument can be a constant argument. The constant variable cannot be changed inside the function definition when the argument is declared as constant.
void f_const(int x, const int y);
void main( )
{int a10, b=20,c;
c =f_const(a, b); //The value of c is 30
}
int f_ref(int x, const int y)
{ //y=20; // Is invalid because y is declared as constant variable. return (x+y);
void f_const(int x, const int y=100);
{int a=200, b,c;
c =f_const(a); //The value of c is 300
int f_const(int x, const int y)
A: no, can't. The names of, precedence of, associativity of, and arity of operators is fixed through the language. In C++, there is no operator** so you cannot create one for a
A: No. (Excluding if you have an old compiler, you might have to force the new operator to throw an exception if it runs out of memory.) This turns out to be a real pain to alwa
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what is c++ ?
decodethecode
It tells the compiler that a variable or a function exists, even if the compiler hasn't yet seen it in the file presently being compiled. This variable or function may be distinct
tel prgm for tis
Write a program to count the prime number in array
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