Consider a Shiny Surface Along With Diffused Reflection coefficient

Consider a shiny surface along with diffused reflection coefficient of 0.8 and ambient reflection coefficient of 0.7, the surface has standard in the direction of 2i + 3j +4k; as several light is incident on it from the direction i + j + k hence the ambient and diffused intensities are of order 2 and 3 units. Find out the intensity or reflected light.

Solution: The combined consequence of ambient and diffused reflection is specified by:

I = I_a K_a + I_d K_d cos θ = I_a K_a + I_d K_d ( N¯ .L¯)

By using the data specified in the equation we find:

I = 2 * 0.7 + 3 * 0.8 * ((2i + 3j + 4k).(i +j +k))

= 1.4 + 2.4 (2 + 3 + 4)

= 1.4 + 9*2.4

= 23