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Consider the following relational schema: PERSON (SS#, NAME, ADDRESS) CAR (REGISTRATION_NUMBER, YEAR, MODEL) ACCIDENT (DATE, DRIVER, CAR_REG_NO) OWNS (SS#, LICENSE)
Construct the subsequent relational algebra queries: (i) Find out the names of persons who are included in an accident. (ii) Find out the registration number of cars that were not involved in any accident. Ans: (i) πNAME(PERSON) ∩ πDRIVER(ACCIDENT) (ii) πREGISTRATION_NUMBER(CAR) - πCAR_REG_NO(ACCIDENT)
composite attribute
Consider the following frequency counts of some itemsets in a transaction database r : freq({A}, r) = 0.405 freq({B}, r) = 0.510 freq({C}, r) = 0.303 freq({A
Consider a research paper submission process. The process starts when an author submits a draft research paper (the paper may have up to 3 authors) to the chair of the organizing c
System level permissions : With the use of data dictionary you can view them. Let us take the table name as user_sys_privs (used in oracle). DESCRIBE USER_SYS_PRI
Difference between Operating System and Database Security Security within the operating system can be executed at various levels ranging from passwords for access to system, t
List the table modification commands in SQL? A) Deletion B) Updates C) Insertion D) Update of a view
What is a block and a block number? A block is a contiguous sequence of sectors from a single track of one platter. Every request specifies the address on the disk to be refere
Question 1 What is data mining? Write Data Mining applications Question 2 What is OLAP? Write the benefits of OLAP Question 3 What is Business Intelligence? Explai
Breaking into Subsystems Decomposition is a significant technique for coping with complexity based on idea of divide and conquers. In dividing a problem into sub problems, the
Locks: Serialisabilty is just a test whether a given interleaved schedule is ok or has a concurrency related trouble. Though, it does not make sure that the interleaved concurrent
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