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The sum of the squares of two consecutive positive odd integers is 74. What is the value of the smaller integer?
Let x = the lesser odd integer and let x + 2 = the greater odd integer. The translation of the sentence, "The sum of the squares of two consecutive odd integers is 74," is the equation x2 + (x + 2)2 = 74. Multiply (x + 2)2 out as (x + 2)(x + 2) by using the distributive property: x2 + (x2 + 2x + 2x + 4) = 74. Combine such as terms on the left side of the equation: 2x2 + 4x + 4 = 74. Put the equation in standard form through subtracting 74 from both sides, and set it equal to zero: 2x2 + 4x - 70 = 0; factor the trinomial completely: 2(x2 + 2x - 35) = 0; 2(x - 5)(x + 7) = 0. Set each factor equal to zero and solve: 2 ≠ 0 or x - 5 = 0 or x + 7 = 0; x = 5 or x = -7. Because you are seems for a positive integer, reject the solution of x = -7. Thus, the smaller positive integer is 5.
Thus, just why do we care regarding direction fields? Two nice pieces of information are there which can be readily determined from the direction field for a differential equation.
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lecturer notes
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