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Let us consider the operation of the EPROM device in more detail. Consider the pining details below again
Before we examine the interface means of the EPROM, it is worth giving the operation a little thought. Each memory cell in the EPROM could store 1 byte of data i.e. 8 1, 0's. In order to access each location the EPROM has to assign each location a unique address, this is used to access the data. This is similar to the concept of a telephone number each house has its own number. The device is constructed to request this address from external pins namely: A0 -> A15. The data pathway to the device is by means of the data bus i.e. DQ0 -> DQ7. The remaining pins of the device are concerned with selecting the device i.e. power on (CE) and reading the data (OE). These additional pins are often termed 'control bus'. The operation of the device to read data is simple in that we:
1) Turn on the device CE =0 2) Present the address on the address pins A0 -> A15 3) Output enable the device to read the data (OE =0) 4) Read the data of the data bus (D7 -> D0) The timing of these operations is sometimes critical since it takes a finite time to access the data, therefore we must be careful not to read the data too quick. This time is termed the access time of the device, for this EPROM it is 150ns. RAM devices are similar in operation besides they have a read/write pin which enables the user to input and output data. The remaining digital systems employ VLSI methods ' Very Large scale integration', these devices are the heart of the modern PC, i.e. microprocessors, complex function devices. Before we discuss microprocessor we really should look at base systems and binary, hexadecimal and deanery systems
The optimal replacement policy, called OPT, is to evict the page which will be accessed farthest into the future. Since we can't predict the future precisely, we can't implement OP
What is super block A partition control block have partitions details, such as the number of blocks in the partition, size of the blocks, free-blocks and free-block pointers an
What are the disadvantages of linked allocation? The drawbacks are a. Used only for sequential access of files. b. Direct access is not supported c. Memory space neede
What are race conditions? Race conditions are problems that take place due to the sharing of the same file by several processes. In such a case none of the processes is able to
What is external fragmentation? As process are removed from and loaded to the memory free memory space is bracken into pieces .external fragmentation take place when enough mem
how do semaphores help us in eliminating deadlock conditions?
Q. Could you replicate a multilevel directory structure with a single-level directory structure in which arbitrarily long names can be used? If your answer is yes describe how you
Single level directory: This is the easiest directory structure. All the files are controlled in the same directory, which is simple to support and understand. Few of the li
What is linked allocation, as detailed in text? Directory has pointers to first and last blocks of file. Every block of file (except last) has pointer to the next block.
my Operating System is windows trust but when the windows start say its windows xp. help pleaes
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