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Question:
(i) Differentiate between ionic, metallic, covalent and dipole-dipole bonds. Provide examples in each case.
(ii) With regard to electronic con?guration, what do all the elements in Group VII of the periodic table have in common?
(iii) Describe why hydrogen ?uoride (HF) has a higher boiling temperature than hydrogen chloride (HCl) (19.4ºC vs. - 85ºC), even though HF has a lower molecular weight.
(iv) On the basis of the hydrogen bond, explain the anomalous behaviour of water when it freezes. That is, why is there volume expansion upon solidi?cation?
(a) Copper has an atomic radius of 0.128 nm, a face-centered cubic crystal structure and an atomic weight of 63.5 g/mol. Compute
(i) the volume of a unit cell of copper
(ii) the atomic packing factor
(iii) the theoretical density of copper.
Q. Apply Kinetic Molecular Theory to Liquids? Ans. The Kinetic Molecular Theory (KMT) states that the particles of liquids are in constant random motion. Their motion, how
various types of medicines use in daily life? and classify them into analgesics, antipyretics, antibiotics, sedatives, antiseptics.
For the dumb-bell shaped orbital, the value of l is: (1) 3 (2) 1 (3) 0 (4) 2 Ans: 1
Evaluation of food quality A common practice employed to evaluate the shelf life of a given food product is to determine changes in selected quality characteristics over a per
density of gas is 2.86 ltr.the gas maz be-
Liquid propellants - Monopropellants and Bipropellants These contain an oxidizer like liquid oxygen, nitrogen tetroxide (N 2 O 2 ) or nitric acid and a fuel for example alcohol
the measured dipole moment of-para nitroaniline (6.2D) is larger than the value calculating using empirical group moment (5.2D)
what are the applications of coordination complexes analyticaly , biologically??
Bond strength in hydrocarbons As much shorter is the bond size, the greater is the compression among molecules atomic nuclei and therefore greater is the strength of that bond.
The expression for Bohr's radius of an atom is: (1) r= n 2 h 2 / 4 Π 2 me 4 z 2 (2) r= n 2 h 2 / 4 Π me 2 z 2 (3) r= n2h2/4 Π me 3
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