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Generally, Computational complexity of algorithms are referred to through space complexity (space needed for running program) and time complexity (time needed for running the program). In computer of science, the concept of runtime complexity has been studied vigorously. Sufficient research is being carried out to determine more efficient algorithms for present problems. We studied several asymptotic notations, to define the time complexity and space complexity of algorithms, say the big-O, Omega & Theta notations. These asymptotic orders of time & space complexity define how best or worst an algorithm is for an adequately large input.
We studied regarding the process of calculation of runtime complexity of several algorithms. The exact analysis of insertion sort was discussed to define the best case, worst case & average case scenario.
Define Strictly Binary Tree Strictly Binary Tree: - If each non leaf node in binary tree has non empty left and right sub-trees , then the tree is known as a strictly binary t
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What is multiple queue and explain them
Q. Reverse the order of the elements on a stack S (i) by using two additional stacks (ii) by using one additional queue. Ans : L e t S be the stac
Post-order Traversal This can be done both iteratively and recursively. The iterative solution would need a change of the in-order traversal algorithm.
A striking application of DFS is determine a strongly connected component of a graph. Definition: For graph G = (V, E) , where V refer to the set of vertices and E refer to the
Which sorting algorithm is easily adaptable to singly linked lists? Simple Insertion sor t is easily adabtable to singly linked list.
Explain the Scan-Line Algorithm This image-space method for removing hidden surfaces is an extension of the scan-line algorithm for filling polygon interiors. Instead of fillin
Q. Construct a complete binary tree with depth 3 for this tree which is maintained in the memory using the linked representation. Make the adjacency list and adjacency matrix for t
Ans: A procedure to reverse the singly linked list: reverse(struct node **st) { struct node *p, *q, *r; p = *st; q = NULL; while(p != NULL) { r =q;
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