complex numbers, Mathematics

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express the complex number z=5+i divide 2+3i in the form a+ib

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Y=θ[SIN(INθ)+COS(INθ)],THEN FIND dy÷dθ. Solution)  Y=θ[SIN(INθ)+COS(INθ)] applying u.v rule then dy÷dθ={[ SIN(INθ)+COS(INθ) ] dθ÷dθ }+ {θ[ d÷dθ{SIN(INθ)+COS(INθ) ] }    => SI

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Solve by factorization X 2 +(a/a+b + a+b/a)x+1 = 0 X 2 +(a/a+b + a+b/a)x+1 =>  X 2 +(a/a+b x a+b/ax + a/a+b .a+b/a) =>  X[x+a/a+b] +a+b/a[a+a*a+b]= 0 =>  X= -a

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