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Evaluate the subsequent integral. Solution This is an innocent enough looking integral. Though, because infinity is not a real number we cannot just integrate as norm
f(x)+f(x+1/2) =1 f(x)=1-f(x+1/2) 0∫2f(x)dx=0∫21-f(x+1/2)dx 0∫2f(x)dx=2-0∫2f(x+1/2)dx take (x+1/2)=v dx=dv 0∫2f(v)dv=2-0∫2f(v)dv 2(0∫2f(v)dv)=2 0∫2f(v)dv=1 0∫2f(x)dx=1
find the newton raphson iterative formula for a reciprocal of a number N and hence find the value of 1/23
Solve : 4x2+2x+3=0 Ans) x^2 + (1/2)x = -(3/4) (x+1/4)^2 = 1/16 - 3/4 = -11/16 implies x = (-1+i(11)^(1/2))/4 and its conjugate.
one half y minus 14
#pqrs is a parallelogram its adjacent side is 2:1.state tHE angles
a ,b,c are complex numbers such that a/1-b=b/1-c=c-1-a=k.find the value of k
show that, sin 90 degree = 2 cos 45 degree sin 45 degree
Circles - Common Polar Coordinate Graphs Let us come across at the equations of circles in polar coordinates. 1. r = a . This equation is saying that there is no matter
Fermat's Theorem If f(x) has a relative extrema at x = c and f′(c) exists then x = c is a critical point of f(x). Actually, this will be a critical point that f′(c) =0.
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