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It is the last case that we need to take a look at. Throughout this section we will look at solutions to the system,
x?' = A x?
Here the eigenvalues of the matrix A are complex. By using complex eigenvalues we are going to have similar problem that we had back while we were looking at second order differential equations. We need our solutions to only have real numbers in them, though as our solutions to systems are of the form,
x?1 = ?h elt
We are going to contain complex numbers come in our solution from both the eigenvector and the eigenvalue. Getting rid of the complex numbers now will be same to how we did this back in the second order differential equation case, although will include a little more work this time around. It's simple to see how to do it in an example.
what will the introduction be ???
If ABCD isaa square of side 6 cm find area of shaded region
63*789
1. Solve the right triangle. B = 135 c = 3.72 A ≈ ____° (round to the nearest tenth as needed) 2. Solve the right triangle, where a =4 and b =10 The length of
write each fraction as a decimal .round to the nearest hundredth if necessary (1-4) (14-21)
trigonometric ratios of sum and difference of two angles
G2=5.12 and G5=80 Find, r, G1, and S6
calculation of emi %
Surface Area with Parametric Equations In this final section of looking at calculus applications with parametric equations we will take a look at determining the surface area o
two circle of radius of 2cm &3cm &diameter of 8cm dram common tangent
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