Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Compatibility Condition:
Total strain in steel = Total strain in copper
i.e. 3 × 10-4 + 1.965 × 10-5 Ps = 4.5 × 10-4 + 1.8421 × 10-5 Pc
Recognising that Pc = - Ps, and dividing both sides by 10-5, we get
30 + 1.965 Ps = 45 - 1.8421 Ps
or Ps = 45 - 30/ (1.965 + 1.8421) = 3.94 kN
∴ Stress in steel = 3.94 × 1000/ (π/4) × 182 = 15.5 N/mm2
∴ Stress in copper = - 3.94 × 1000/ (π /4)(302 - 182) = - 8.71 N/mm2
A No 10 steel rebar is tested in tension by monitoring the load reading of the testing machine it was found that the specimen yielded at aload of 41600lb and fractured at 48300 lb
chemical compositions of Rapid Hardening Cement
Question Would a concrete structure be entirely free of expansion joints and contraction ? Answer Consider that concrete structure is not subject to problem of disparity settlem
#questof obstacles to both chaining and ranging. ion..
what type of ethics is environmentel ethics
radial line method practical
which Subject that wants civil engineers?
briefly explain about c tokens ?
Determine the Loss in post-tensioned members This loss occurs only in post-tensioned members. There always exists a certain amount of friction in the jacking and anchoring syst
1. Elastomeric bearings must not be placed one behind the other along the longitudinal axis of the girder on a single line of support under any circumstances. 2. Bearings of dif
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd