Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Compatibility Condition:
Total strain in steel = Total strain in copper
i.e. 3 × 10-4 + 1.965 × 10-5 Ps = 4.5 × 10-4 + 1.8421 × 10-5 Pc
Recognising that Pc = - Ps, and dividing both sides by 10-5, we get
30 + 1.965 Ps = 45 - 1.8421 Ps
or Ps = 45 - 30/ (1.965 + 1.8421) = 3.94 kN
∴ Stress in steel = 3.94 × 1000/ (π/4) × 182 = 15.5 N/mm2
∴ Stress in copper = - 3.94 × 1000/ (π /4)(302 - 182) = - 8.71 N/mm2
Figures (a) and (b) respectively give details of a simply-supported bridge beam and its (idealised) cross-section. In addition to the dead load of 25 kN/m (including self weight),
Describe why soils are compacted in the field. How is the degree of compaction ensured in the field (i.e., control of field compaction)? Distinguish among 'compaction' and 'consoli
grading surface area of Aggregate
which IS code give details about Strength of Brick?
calculating included angle and bearing
1feet
what is meant by bars of uniform strength
i need journals or articles of forensic structural engineering
Explain briefly physical classifications of stone
if the slump of concrete drops how to rectify it
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd