Comparison between 8086 and 8088, Assembly Language

Assignment Help:

Comparison between 8086 and 8088

All the changes in 8088 above 8086 are indirectly or directly related to the 8-bit, 8085 compatible data and control bus interface.

1) The predecoded code queue length is reduced to 4 bytes in 8088, whereas the 8086 queue have 6 bytes. This was done to get ride from the unnecessary prefetch operations and optimize the use of the bus by BIU when prefetching the instructions.

2) The 8088 bus interface unit will fetch a byte from memory to load the queue each time, if at least one byte is free. In case of 8086, at least two bytes should be free for the next fetch operation.

3) The whole execution time of the instructions in 8088 is affected by the 8-bit external data bus. Now all the16-bit operations require additional 4 clock cycles. The CPU speed is also restricted by the speed of instruction fetches.

 

The pin assignments  of both the CPUs are closely identical, however, they have the following functional changes.

1.) A8-A15 already latched, every time valid address bus.

2. ) BHE has no meaning as the data bus is only of 8-bits.

3.) SS0 provides the S0 status information in  theminimum mode.

4.) IO/M has been inverted to be compatible with 8085 bus structure

 


Related Discussions:- Comparison between 8086 and 8088

Dq-dt-assemblers directive-microprocessor, DQ:   Define  Quad word:-  Th...

DQ:   Define  Quad word:-  This directive is taken in use to direct the assembler to reserve 4 words (8 bytes) of memory for the specified variable and can initialise it having

Linking a program-microprocessor, Linking a program The DOS linking pro...

Linking a program The DOS linking program LINK.EXE links the different object modules of function library routines and source program to produce an integrated executable code o

Matlab?., Hello, I just want to know how much would it cost for you to deve...

Hello, I just want to know how much would it cost for you to develop , debug and test a program in matlab to solve a system of equations with gauss elimination with partial pivotin

Memory segmentation-microprocessor, Memory Segmentation : The  memory ...

Memory Segmentation : The  memory in an 8086/8088  based system is organized as segmented memory. In this scheme, the whole physically available memory can be divided into a n

Physical memory mapped and port input output-microprocessor, Physical Memor...

Physical Memory Mapped I/O and Port I/O : CPU controlled I/O comes in 2 ways. Simply the difference is whether we utilize the normal memory addresses for I/O, this is mention

Program to add 8-bit series numbers-assembly language, Program: Write a pr...

Program: Write a program to perform addition of a series of 8-bit numbers. The series have 100 (numbers). Solution : In the first program, we have been implemented the add

Write a assembly language subroutine, Write a M68000 assembly language subr...

Write a M68000 assembly language subroutine MULSUM that takes an array named A containing n bytes of positive numbers, and fills two arrays, array B containing n

Relocate program and data, ) What is the difference between re-locatable pr...

) What is the difference between re-locatable program and re-locatable data?

Assembly Language Program, which uses BIOS interrupt INT 21 to read current...

which uses BIOS interrupt INT 21 to read current system time and displays it on the top-left corner of screen.

Assignment, Write an assembly program that adds the elements in the odd ind...

Write an assembly program that adds the elements in the odd indices of the following array. Use LOOP. What is the final value in the register?

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd