Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Compare user threads and kernel threads.
User threads:-
User threads are supported above the kernel and are executed by a thread library at the user level. Thread creation & scheduling are done in the user space, without kernel intervention. Thus they are fast to create and manage blocking system call will cause the whole process to block
Kernel threads:-
Kernel threads are supported directly by the operating system .Thread creation; scheduling and management are completed by the operating system. Thus they are slower to create & manage compared to user threads. If the thread performs a blocking system call, the kernel can schedule another thread in the application for implementation.
How do we overcome the disadvantages of the two-level directory? Give links from one user directory to another, creating path names; system files become available by letting th
What are the four necessary conditions of deadlock prevention? Ans: Four essential conditions for deadlock prevention: a. The meaning of removing the mutual exclusio
Consider the following snapshot of a system, answer the following questions using the banker's algorithm: 1. What is the content of the matrix Need? Is the system in a safe stat
Q. Describe the concept of transaction atomicity? Answer: A transaction is a sequence of read as well as writes operations upon some data followed by a commit operation. If the
Q. Definition of Operating System? Definition of Operating System: • An Operating system is a program which controls execution of application programs and acts as an interfa
There is a process bloacked by a semaphore and no other process in the ready queue, can the blocked process get back to the ready queue without the semsignal() function?
Q. Presume that a system is in an unsafe state. Illustrate that it is possible for the processes to complete their execution without entering a deadlock state. Answer: An unsaf
Example 1. The diagram illustrating the data structures of in-memory VFS objects and on-disk objects and their relationships on slide 24 of the lecture notes OSD.4. This diagram i
define monolathic structure
Q. A Burroughs B7000/B6000 MCP file is able to be tagged as sensitive data. When such a file is removed its storage area is overwritten by some random bits. For what reason would
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd