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Jocko's Garage has been accused of insurance fraud. Data on estimates made by Jocko and another garage were obtained for 10 damaged vehicles (available in 'jockogarage.txt'). Here is what the investigators foundCar 1 2 3 4 5Jocko's 1375 1550 1250 1300 900Other 1250 1300 1250 1200 950Car 6 7 8 9 10Jocko's 1500 1750 3600 2250 2800Other 1575 1600 3300 2125 2600(a). Compute the mean estimate for Jocko and the mean estimate for the other garage. Report the di erence in the means and the 95% con dence interval used on the t procedure. Be sure to choose the appropriate t procedure for your analysis and explain why you made this choice.
(b). Use a non-parametric tool discussed in this course to test if the average estimate from Jocko's is larger than the other garage for 100.Hint: No! I am sure that the problem is NOT wrong.
(c). Use a bootstrap scheme to nd the con dence interval of the di erence. Be sure to provide details (since I need to replicate your result if necessary) about how you used the bootstrap and explain why it is reasonable briefly.
(d).Compare the t interval with the bootstrap interval
who invented the chi square test and why? what is central chi square and non central chi square test? what is distribution free statistics? what are the conditions when the chi squ
Q. 1 a) Describe the important quantitative techniques used in public system management. (10) b) Do you think the day will come when all decisions are made with the assistance of
Standard Deviation The main drawback of the deviation measures of dispersion, as discussed earlier, is that the positive and negative deviations cancel out each other. Use of t
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The cornlnunalities h j represent the fraction of the total variance' 'accounted for of variabie j. Ry calculating the communalities we can keep track of how much of-the orig
Ask question #MinimumA wedge is small piece of material having two of their opposite faces not parallel. To lift block of weight W, it is pushed by horizontal force P which lifts t
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Arithmetic Mean The process of computing Arithmetic Mean in the case of individual observations is to take the sum of the values of the variable and then divide by the number
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Ten balls are put in 6 slots at random.Then expected total number of balls in the two extreme slots
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