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Two resistances have lengths in the ratio 1:4 and radius 1:2,specific resistances in ratio 3:1. compare their resistances.Solution)Given lengths l1=1 l2=4Given radius r1=1 r2=2 Given specific resistances Ρ(rho)1=3 Ρ2= 1we know the R=Ρl/A R1/R2=3/1.
Description about mauls law
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what does it result?
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