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The topic along with functions which we ought to deal with is combining functions. For the most part this means performing fundamental arithmetic (subtraction, addition, multiplication, & division) with functions. There is one new means of combing functions which we'll need to look at as well.
Let's begin with basic arithmetic of functions. Given two functions f(x) & g(x) we have the following notation & operations.
( f + g )( x) =f ( x ) + g ( x ) ( f - g )( x ) =f ( x ) - g ( x )
( fg ) ( x ) = f ( x ) g ( x ) (f /g) ( x ) = f ( x )/ g ( x )
Sometimes we will drop the ( x )part & just write down the following,
f + g = f ( x ) + g ( x ) f - g=f ( x ) - g ( x )
fg =f ( x ) g ( x ) f/g = f ( x ) /g ( x )
Note as well that we put x's in the parenthesis, however we will frequently put in numbers as well.
(2/9+4/9)(1/3-5/8)
I need help solving -5=1/4(4+20r)-8r
brief explanation
To estimate the size of the bear population in Keweenaw Pennisula, conservationists captured, tagged and released 50 bears. One year later, a random sample of 100 bears included on
x-4
how do you do it
7a + 6b = 14 -7a + b =35 solve by the elimination method
w2+30w+81 need step by step and explanation.
Now, let's solve out some double inequalities. The procedure here is alike in some ways to solving single inequalities and still very different in other ways. As there are two ineq
I dont understand why the least common denominator to the problem (3/2x) minus (1/2(x+10)) equals 1 is 2x(x+10)
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