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GROUP 14: TIN AND LEAD Tin and lead give some resemblance to the lighter elements in group 14, especially Ge. Although they are uniquely more metallic in their physical and chem
17.4g CaCO3= mol O
classify the reaction.Na2CO3(s) + SiO2(s) ? Na2SiO3(l) + CO2(g)
(a) Given the values below, calculate the concentration of benzoyl peroxide required to prepare polystyrene with a number average molar mass of 400,000 by bulk free radical polymer
Number of unpaired electrons in inert gas is: (1) Zero (2) 8 (3) 4 (4) 18 Ans: Zero
does SnCl4 = Tin Chloride
Q. Explain about Magnetic Separation ? This process is based on the difference in magnetic properties of minerals. If the ore but not the gangue is attracted by a magnetic fiel
Q. Illustrate Chemical nomenclature? Ans. Chemical nomenclature is the system of names that chemists use to identify compounds precisely. The systematic method of naming c
what is p block element
Q. Explain Lead chamber process? Lead chamber process, is the older of the two processes. In this process SO 2 , is produced by burning S or roasting pyrites. S + O 2 -
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