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A body of mass m1 , moving with velocity u1 collides head on with a body of mass m2 moving with a velocity u2 the two bodies stick together after the collision the loss of kinetic energy after the collision is ?Ans) Initial KE of the system= 1/2 [ m1.u1^2 + m2.u2^2 ]applying conservation of momentum we get new velocity of the new body= (m1.u1-m2.u2) / (m1+m2)new KE of the Body= [ (m1.u.1 - m2.u2) / 2.(m1+m2) ]^2Subtracting and simplyfing we get the loss in KE after Collision= [ m1.m2. (u1 + u2)^2 ] / [ 2.(m1 + m2) ]
Q. Escape Velocity An object will conquer the force of gravity when its kinetic energy in the direction away from earth exceeds its potential energy. We find the smallest kinet
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A boy throws a ball of mass 20 kg vertically upwards.It raises to a maximum height of 100 m.At what height will the kinetic energy be reduced to 70%?
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a car of mass 800kg is pulling a trailer 300kg where sin a=1|200.Resistance to motion(apart from gravity) is 1.5N per kg of mad for each vehicle.calculate the pulls of the engine
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A bat emits a sound whose frequency is 142 kHz. The speed of sound in air at 20.0°C is 343 m/s. However, the air temperature is 35°C, so the speed of sound is not 343 m/s. Find the
Since the objects stick together they will be a part of plastic collision...so. conservation of kinetic energy cannot be applied...Apply conservation of linear momentum and then find individual velocitiesthen loss of kinetic energy will be change in kinetic energy......So,it will become equal to amount of work done.
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