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Specified the code segment below and that n is the problem size, answer the following queries:
// . . .
int sum = 0;
if(x > 12){
for(int i = 1; i <= n; i = i * 2) for( intk = 0; k< n * n; k++) sum++; // statement1
}
else{
for(int i = 1; i <=n; i++) sum++; // statement2
for(int i = 1; i <= n; i = i +4) sum++; // statement3
for(int i = 1; i <= n; i++) for( intk = 1; k<= n; k = k * 2) sum++; // statement4
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usability of union
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