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We need a serious programmer who will code Java and Javascript in Liferay - open to bidding Project Description: Big Data project Prototype in Liferay. Big Data + User onl
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I can''t figure out how to do this question: "Given two linear equations: ax + by + c = 0 and dx + ey + f = 0" solve for x and y. A, b, c, d, e, and f being inputted from the user.
RMI is a set of APIs that permits to build distributed applications. RMI uses interfaces to explain remote objects to turn local method invocations into remote method invocations.
Relate Java with C/C++ Very similar C/C++ syntax, operators, etc. Core language is simpler than C++ -- no pointers, no operator overloading, and no multiple inheritance.
The roster lets you keep track of the availability ("presence") of other users. A roster also allows you to organize users into groups such as "Friends" and "Co-workers". Other IM
How can you justify that a DBMS is better to use than Flat-file database? A DBMS takes care of the storage, retrieval, and management of large data sets on a Database. It give
What is a variable in Java program? It's a memory location. Memory location is given some name. Memory location is being assigned some value. Value may change o
I need Android Kiosk Mode Project Description: I need an Android platform developer to develop an app when device start it start into kiosk mode. Only browser window open a c
Describe the relational operators in java? Java has six relational operators which compare two numbers and return a boolean value. The relational operators are , > , , >=
package test.padovanstring;public class PadovanString {public int stringOccurrences(int n, String str){if(n >= 40)return -1;if(str.replaceAll("X|Y|Z","").length()>0)return -1;String res=pad(n);return(res.length() - res.replaceAll(str,"").length())/(str.length());}public String pad(int n){if(n == 0) return "X";if(n == 1) return "Y";if(n == 2) return "Z";else return pad(n-2) + pad(n-3);}public static void main(String []args){PadovanString p = new PadovanString();System.out.println(p.stringOccurrences(21,"YZ"));}}
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