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CMPS : Compare String Byte or String Word:-The CMPS instruction may be utilized to compare two strings of Words or byte. The length of the string ought to be stored in the CX. If both the word or byte strings are equal, zero flag is set. Flags are affected in the similar way as CMP instruction. The DS: SI and ES: DI point to the 2 strings. The REP instruction prefix is utilized to repeat the operation till register CX (counter) becomes zero or the condition specified by the REP prefix is false.
Following string of instructions describe the instruction. Comparison of the string begin from initial byte / word of the string, after each comparison the index registers are updated depending on the direction flag and the counter is decremented. This byte by byte / word by word comparison continues until a mismatch is found. When, a mismatch is found, the carry flag and zero flags are modified properly and the execution proceeds further.
Example :
If both strings are fully equal, for example the register CX becomes zero, the ZF is set, or else, ZF is reset.
Write an assembly language program that will display (print) a list of the Decades 2010, 2020, 2030... 2100 to the screen using a while loop.
what will be the value of EAX after following instructions execute? mov bx, 0FFFFh and bx, 6Bh
Hello
how to add 111 and 333 in assembly language
AND: Logical AND: This instruction bit by bit ANDs the source operand that might be an immediate, or a memory location or register to the destination operand that might be a memor
Queue Operation : RQ/CT0, RQ/G1-Request/Grant: These pins are utilized by other local bus masters, in themaximum mode, to force the processor to release the loca
Open notepad and enter the code for a program that calculates the following arithmetic expression: x = a + b + c - d - e + f The operands a, b, c, d, e, f, and x should be declared
Mov ax, [1234h: 4336h + 100]
which uses BIOS interrupt INT 21 to read current system time and displays it on the top-left corner of screen.
Problem (a) Prepare the assembly code sequence for each of the four styles (accumulator, memory-memory, stack, load/store) of machine for the code fragment: A = B + C;
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