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CMPS : Compare String Byte or String Word:-The CMPS instruction may be utilized to compare two strings of Words or byte. The length of the string ought to be stored in the CX. If both the word or byte strings are equal, zero flag is set. Flags are affected in the similar way as CMP instruction. The DS: SI and ES: DI point to the 2 strings. The REP instruction prefix is utilized to repeat the operation till register CX (counter) becomes zero or the condition specified by the REP prefix is false.
Following string of instructions describe the instruction. Comparison of the string begin from initial byte / word of the string, after each comparison the index registers are updated depending on the direction flag and the counter is decremented. This byte by byte / word by word comparison continues until a mismatch is found. When, a mismatch is found, the carry flag and zero flags are modified properly and the execution proceeds further.
Example :
If both strings are fully equal, for example the register CX becomes zero, the ZF is set, or else, ZF is reset.
LODS : Load String Byte or String Word:- The LODS instruction loads AL/AX register by the content of a string pointed to by DS:SI register pair. The SI is automatically modifie
I need a text conversion program written in assembly language
SHR : Shift Logical Right: This instruction performs bit-wise right shifts on the operand word or byte that might be reside in a memory location or a register, by the specified c
OR: Logical OR: The OR instruction carries out the OR operation in the similar way as described in case of the AND operation. The restriction on source and destination operands ar
move a byte string ,16 bytes long from the offset 0200H to 0300H in the segment 7000H..
init_lcd ;(this initialises a 2 row lcd) bcf TRISA,0 ;PORTA bit 0 as an output (lcd RS pin) bcf TRISA,1 ;PORTA bit 1
this is my first project i dont know where to start
1. Write a program that calculates the Fibonacci series: 1, 1, 2, 3, 5, 8, 13, ….. (Except for the first two numbers in the sequence, each number is the sum of the preceding two n
Task One Produce a menu such as the one below (remember to keep to this specification). M E N U 1, Enter Number 1 2, Enter Number 2 3, Display num1 and num2 4, D
Flag Register : 8086 has a 16-bit flag register which is divided into 2 parts, viz. (a)machine control flagsand (b)condition code or status flags. The condition code flag regi
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