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CMPS : Compare String Byte or String Word:-The CMPS instruction may be utilized to compare two strings of Words or byte. The length of the string ought to be stored in the CX. If both the word or byte strings are equal, zero flag is set. Flags are affected in the similar way as CMP instruction. The DS: SI and ES: DI point to the 2 strings. The REP instruction prefix is utilized to repeat the operation till register CX (counter) becomes zero or the condition specified by the REP prefix is false.
Following string of instructions describe the instruction. Comparison of the string begin from initial byte / word of the string, after each comparison the index registers are updated depending on the direction flag and the counter is decremented. This byte by byte / word by word comparison continues until a mismatch is found. When, a mismatch is found, the carry flag and zero flags are modified properly and the execution proceeds further.
Example :
If both strings are fully equal, for example the register CX becomes zero, the ZF is set, or else, ZF is reset.
CMPS : Compare String Byte or String Word:-The CMPS instruction may be utilized to compare two strings of Words or byte. The length of the string ought to be stored in the CX. If
AND: Logical AND: This instruction bit by bit ANDs the source operand that might be an immediate, or a memory location or register to the destination operand that might be a memor
from pin description it seems that 8086 has 16 address/data lines i.e.AD0_AD15.The physical address is however is larger than 2^16.How this condition can be handled
Write a nonrecursive version of the Factorial procedure (Section 8.3.2) that uses a loop. (A VideoNote for this exercise is posted on the Web site.) Write a short program that inte
programs
Addressing mode of 8086 : Addressing mode specify a way of locating operands or data. Depending on the data types used the memory addressing modes and in the instruction ,
1. Write an assembly program that adds the elements in the odd indices of the following array. Use LOOP. What is the final value in the register? array1 DWORD 10, 20, 30, 40, 50, 6
program to find negative and positive integers from given signed numbers with output and explanation of every instructions.
i have a question.
add the contents of the defined memory locations 120, 133, 122 using mov instruction in dosbox
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