Class of recognizable languages, Theory of Computation

Assignment Help:

Proof (sketch): Suppose L1 and L2 are recognizable. Then there are DFAs A1 = (Q,Σ, T1, q0, F1) and A2 = (P,Σ, T2, p0, F2) such that L1 = L(A1) and L2 = L(A2). We construct A′ such that L(A′ ) = L1 ∩ L2. The idea is to have A′ run A1 and A2 in parallel-keeping track of the state of both machines. It will accept a string, then, iff both machines reach an accepting state on that string.

Let A′ = (Q × P,Σ, T′ , (q0, p0), F1 × F2), where

T′ def= [{((q, pi, (q′, p′), σ) | (q, q′, σi)∈ T1 and (p, p′, σ ∈ T2}.

2294_Class of recognizable languages.png

Then

(You should prove this; it is an easy induction on the structure of w.) It follows then that

751_Class of recognizable languages1.png


Related Discussions:- Class of recognizable languages

Bonds, . On July 1, 2010, Harris Co. issued 6,000 bonds at $1,000 each. The...

. On July 1, 2010, Harris Co. issued 6,000 bonds at $1,000 each. The bonds paid interest semiannually at 5%. The bonds had a term of 20 years. At the time of issuance, the market r

Assignment, Consider a water bottle vending machine as a finite–state autom...

Consider a water bottle vending machine as a finite–state automaton. This machine is designed to accept coins of Rs. 2 and 5 only. It dispenses a single water bottle as soon as the

Instantaneous description - recognizable language, De?nition (Instantaneous...

De?nition (Instantaneous Description) (for both DFAs and NFAs) An instantaneous description of A = (Q,Σ, δ, q 0 , F) , either a DFA or an NFA, is a pair h q ,w i ∈ Q×Σ*, where

Hhhhhhhhhhhhhhhhh, Ask question #hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh...

Ask question #hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhMinimum 100 words accepted#

Pumping lemma constant, a) Let n be the pumping lemma constant. Then if L i...

a) Let n be the pumping lemma constant. Then if L is regular, PL implies that s can be decomposed into xyz, |y| > 0, |xy| ≤n, such that xy i z is in L for all i ≥0. Since the le

Equivalence of nfas, It is not hard to see that ε-transitions do not add to...

It is not hard to see that ε-transitions do not add to the accepting power of the model. The underlying idea is that whenever an ID (q, σ  v) directly computes another (p, v) via

Finite automata, design an automata for strings having exactly four 1''s

design an automata for strings having exactly four 1''s

Non - sl languages, Application of the general suffix substitution closure ...

Application of the general suffix substitution closure theorem is slightly more complicated than application of the specific k-local versions. In the specific versions, all we had

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd