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Can I drop the [] while deleteing array of some built-in type (char, int, etc)?
A: No. you can't
Sometimes programmers think that the [] in the delete[] p only present so the compiler will call the suitable destructors for all elements in the array. Due to this reasoning, they suppose that an array of some built-in type such as char or int can be deleted without the []. For example they suppose the following is valid code:
void userCode(int n)
{
char* p = new char[n];
...
delete p; // ERROR! Should be delete[] p !
}
However the above code is wrong and it can cause a blow at runtime. Particularly, the code that's called for delete p is operator delete (void*), however the code that's called for delete[] p is operator delete[](void*). For the latter the default behavior is to call the former, however users are allowed to replace the latter along with a different behavior (in which case normally they would also replace the corresponding new code in operator new[](size_t)). If they replaced the delete[] code thus it wasn't compatible along with the delete code, and you called the wrong one (that means if you said delete p instead of delete[] p), you could end up with a disaster at runtime.
Virtual Base Classes This ambiguity can be resolved if the class derived have only one copy of the class base. This can be done by making the base class a virtual class. This k
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