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Can copy constructor admit an object of the same class as parameter, rather than reference of the object?
A: Here are a few of the many instance of operator overloading: myString + yourString may concatenate two std::string objects myDate++ may increment a Date object a * b may m
A: BinarySearchTree.h ---------------------- #ifndef BINARY_SEARCH_TREE_H_ #define BINARY_SEARCH_TREE_H_ #include "dsexceptions.h" #include // For NULL // Binary
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Q: Tells the operators one can override; which operators should he override? A: Bottom line: don't puzzle your users. Remember the reason of operator overloading: to decreas
A: No. this is specified in the definition of the copy constructor itself. It must generate an error if a programmer specifies a copy constructor along a first argument that is an object and not a reference.
constructor with a single argument creates that constructor as conversion ctor and it can be utilized for type conversion. For instance: class Boo { public: Boo ( int i ); }; Boo BooObject = 10; // assigning int 10 Boo object
constructor with a single argument creates that constructor as conversion ctor and it can be utilized for type conversion.
For instance:
class Boo
{
public:
Boo ( int i );
};
Boo BooObject = 10; // assigning int 10 Boo object
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