Cam-cam illustrations, Mechanical Engineering

Assignment Help:

Cam

This is a mechanical member that imparts motion to another member called follower.

Illustration:

A cam is rotating at regular speed of 1200 rpm in the clockwise direction. This operates a roller following of 20 mm diameter having the data given as:

Minimum diameter of the cam = 60 mm
Maximum lift = 50 mm
Angle for rise with equivalent uniform acceleration and retardation = 120o
Angle for dwell after rise = 60o
Angle for return having equal uniform acceleration and retardation = 90o

Find out maximum acceleration & maximum velocity of the follower throughout rise and return.

Solution:

Maximum lift (L) = 50 mm, Angle for rise (θo) = 120o, Angle for return (θr) = 90o
The first step is to draw displacement diagram for the follower by supposing suitable scale.

(a) While follower axis passes through cam centre

(i) Draw a circle having radius equivalent to minimum radius of the cam to the scale that was decided for displacement diagram. Draw another circle having the similar centre having radius equal to (min. radius of cam + roller radius).

(ii) Show the sense of rotation & initial position of the roller.

(iii) Supposing cam stationary, follower is taken approximated it in the sense opposite to the sense of rotation of the cam. Beginning from initial location, mark angle for rise or ascent that means θo. After that mark for dwell period & then mark for return or descent angle say θr.

(iv) Divide angles θo & θr into similar number of equal pars like this is done in displacement diagram and in this case this is 8 equivalent parts. Draw radial lines.

(v) On extended radial lines transfer the equivalent displacement of the follower from displacement diagram above, the, prime circle (base circle radius + roller radius), that means 1 – 1′, 2 – 2′, etc.

(vi) Draw a series of arcs of radii equivalent to roller radius to defined roller positions from points 1′, 2′, 3′, 4′, etc.

(vii) Draw a smooth curve tangential to every arc of these to obtain the required cam profile.

806_1.jpg

Maximum velocity during rise =

1911_2.jpg

 Maximum velocity during return =

439_3.jpg

  Maximum acceleration during rise =

2124_4.jpg

 
Acceleration during return =

2087_5.jpg

 
(b) While follower axis is eccentric to the right

(i) Draw three concentric circles having radii equivalent to eccentricity, minimum cam radius and (minimum cam radius + roller radius).
(ii) Cam is supposed stationary, mark initial location of the follower that is tangential to the eccentricity circle, that means A – O′. The follower is taken about the cam in the sense opposite to the cam rotation. The follower axis shall always remain tangential to the eccentric circle.
(iii) Join O – O′. Having this line a zero angle line, mark angle for rise θo, dwell angle & angle for return θr.
(iv) Divide angle for rise θo & angle for return θr into similar number of equivalent parts like it is done in displacement diagram & in this case this is 8 equivalent parts and gets points, 1, 2, 3 . . . 17 on the prime circle.
(v)    Draw tangents on the eccentricity circle from points 1, 2, 3, etc.
On the extended tangent lines, transfer the equivalent displacement of the follower from displacement diagram above prime circle that is 1 – 1′, 2 – 2′, etc. Repeat (e) & (f as denoted in past (a) of this instance to get the needed cam profile.

 


Related Discussions:- Cam-cam illustrations

Valve clearance and tappet adjustment, Valve Clearance and Tappet Adjustmen...

Valve Clearance and Tappet Adjustment: Like all metal components the valve expands on heating. Hence the valve clearance is set so that on expansion there is room for the valve to

Heavy load supports, A number of heavy items are to be off-loaded from a He...

A number of heavy items are to be off-loaded from a Heavy-Lift Ship and placed on a series of "support assemblies" on the quayside to await transportation by road to their destinat

Steps for solving problem for finding maximum power, Step s for Solving Pr...

Step s for Solving Problem for Finding Maximum Power: 1. Use formula stress (σ) = force (Maximum Tension)/Area Where;  Area = b.t that is, T max = σ.b.t 2. Unit mass (

Either wheel is wobbling motorcycle problem, If Either Wheel is Wobbling ...

If Either Wheel is Wobbling Causes of Problem Remedy Excessive wheel bearing play Distorted rim Improperly

Corrosion resistance of tantalum, Q. Corrosion resistance of tantalum? ...

Q. Corrosion resistance of tantalum? Tantalum is readily attacked by strong alkalis, even at room temperature, and therefore, is not suitable for use in processes where the pH

Explain gear forming, Explain Gear Forming In gear form cutting, cuttin...

Explain Gear Forming In gear form cutting, cutting edge of the cutting tool has a shape similar with the shape of the space among the gear teeth. Two machining operations, mill

Wall thickness tank, What must be thickness of Wall tank: ASTM 285 C, const...

What must be thickness of Wall tank: ASTM 285 C, construction material. 15.75 ft diameter 18.0 ft length Wall length down cone =10.4 ft length top cone = 8.3 ft Operation pressur

Calculate composition and microstructure, It is desired to produce an iron-...

It is desired to produce an iron-carbon alloy that has a minimum hardness of 200 HB and a minimum ductility of 35%RA. Is such an alloy possible? If so, what will be its composition

MATLAB CODE, I NEED A GENERALIZED CODE FOR VAPOUR COMPRESSION REFRIGERATION...

I NEED A GENERALIZED CODE FOR VAPOUR COMPRESSION REFRIGERATION SYSTEM?

Define myocardial oxygen uptake, Q. What do you understand by Myocardial Ox...

Q. What do you understand by Myocardial Oxygen Uptake? VO 2 max = Maximum C.O x Maximum A-V Oxygen difference. It is the maximum amount of oxygen that the person can use du

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd