Calculus, Mathematics

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Show that af+bd+ce=ae+bf+cd= 1/2 , In figure, the incircle of triangle ABC...

In figure, the incircle of triangle ABC touches the sides BC, CA, and AB at D, E, and F respectively. Show that AF+BD+CE=AE+BF+CD= 1/2   (perimeter of triangle ABC), Ans:

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1) Let the Sample Space S = {1, 2, 3, 4, 5, 6, 7, 8}. Suppose each outcome is equally likely. Compute the probability of event E = "an even number is selected". P(E) = 2) A s

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