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A multimode step index fibre along with a core diameter of 80µm and a associative refractive index difference of 1.5% is operating at a wavelength of 0.85µm. If the core refractive index is 1.48, calculate the V number and the number of guided modes. Given, core diameter, d=80µm Δ=1.5%=0.015 Λ=0.85µm n1=1.48We know that Numerical Aperture, Sinψ = n1 (2Δ)½ =1.48 (2 x 0.015)½ =0.2563 i.e. (n12- n22)½ =0.2563 (1.482- n22)½ =0.2563Squaring, 1.482- n22 =0.0657 i.e. n2=1.4576We know that V number is given through V= Πd (n12- n22)½ / Λ Substituting the values for d, n1, n2 and Λ, we get V=75.78Take V=76
Number of modes= V2 /2= 762 /2 = 2888
This question is designed to give you practice in manipulating circuit equations using j notation, and to demonstrate that techniques that you have already studied in the d.c. c
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