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Q. A light of wavelength 58900A falls normally on a thin air film, 6 dark fringes are seen between two points. Calculate the thickness of the film.
2μt = nλ
Thickness of the film t = nλ/ 2μ
= 6 X 5890 X 10 -10/ 2
= 1.767 X 10-6 m.
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