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An employee record has the following structure struct employee { int eno; char name[22]; float salary; char dept[10];};(i) Calculate the record size R in bytes.(ii) If the file has 500 records, calculate the blocking factor bfr and the number of blocks b, assuming an unspanned organization with block size B = 512 bytes.(iii) Describe the unused space in each block and in the last block?
Ans: (i) 2 + 22+ 4 + 10 =38 bytes (ii) bfr = floor( B/R) = [512/38] =13 Number of blocks b = ceiling (500/13) =39 (iii) Unused space in each block = 512 - 38 *13 = 512 - 494= 18 bytes Unused space in the last block = ( 39 *13 - 500) * 38 bytes = (507 -500) * 38 bytes = 7 * 38 =266 bytes
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