Calculate the open circuit voltage, Electrical Engineering

Assignment Help:

This question is designed to give you practice in manipulating circuit equations using j notation, and to demonstrate that techniques that you have already studied in the d.c. context can be applied equally successfully to the solution of steady-state a.c. problems.

485_Calculate the open-circuit voltage.png

The sketch (right) shows the approximate equivalent circuit of a real transformer (inside the dotted line) with its parameters referred to the primary side, and with a referred load resistance of 5 ω. Find

(a) the open-circuit voltage VL , and

(b) the voltage across the 5 ω 'referred' load, by the following three methods.

 Method 1: Direct approach. First find the open circuit voltage by simple 'potential divider' approach (but with complex impedances Z replacing the simple resistances we used under d.c. conditions). Then find the equivalent series impedance of the two parallel branches on the right, and again use the 'potential divider' idea to find VL. The calculations are lengthy, and you will probably find it best to use polar form for the multiplications and divisions.

Method 2: Thévenin. Find the Thévenin equivalent circuit for the transformer and 100 V supply. Then apply the load and use the potential divider approach.

Method 3: Nodal Analysis. Call the node at the top of j35 node a and that at the top of the 5 ω load node b, with the reference (zero) node at the bottom. Write down the nodal equations in terms of the complex impedances, and solve for Vb.

Calculate the % change in the output voltage when the load is applied (this is known, as the 'regulation'). What would you expect the regulation to be if the transformer were ideal?


Related Discussions:- Calculate the open circuit voltage

Calculate the cross-sectional area, Calculate the cross-sectional area, in...

Calculate the cross-sectional area, in mm 2 , of a piece of aluminium wire 100 m long and having a resistance of 2Ω. Take the resistivity of aluminium as 0.03 x 10-6 Ωm.

Equivalent circuit of a polyphase induction machine, Equivalent Circuit of ...

Equivalent Circuit of a Polyphase Induction Machine The inductionmachinemay be regarded as a generalized transformer inwhich energy is converted and electric power is transferr

Add instruction , ADD Instruction Op code  format  of ADD instruction...

ADD Instruction Op code  format  of ADD instruction is Replace  the three bit code  of the register R from   to obtain the op code of the  required ADD instruction . op co

Electrical machine, transformer voltage induced in armatur of ac commentato...

transformer voltage induced in armatur of ac commentator machin in case tha field flux in sinosoidal?..

Difference between div and idiv instructions, Mention how do the DIV & I...

Mention how do the DIV & IDIV instructions differ in their functionality DIV: Unsigned numbers division and IDIV: Signed number division.

Explain how leds are arranged in a seven segment display, Q. Explain how LE...

Q. Explain how LEDs are arranged in a seven segment display ? The illustration given below shows the basic layout of the segments in a seven- segment display. The segments the

Transistor, Various compensation techniques

Various compensation techniques

Find the efficiency of the transformer, Q. Athree-phase, 600-kVA, 2300:230-...

Q. Athree-phase, 600-kVA, 2300:230-V,Y-Ytrans- former bank has an iron loss of 4400 W and a full- load copper loss of 7600 W. Find the efficiency of the transformer for 70% full lo

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd