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By what percentage should the pressure of a given mass of gas be increased,so as to decrease its volume by 10% at a constant temperature.
A strip of aluminium of mass 40.7g is dropped into a beaker of dilute hydrochloric acid. Calculate the work done (in J) on the surrounding atmosphere (1atm pressure, 26.1 o C ) by
A car of mass 1.35 x 10 3 kg sits on a large piston that has a surface area of 1.23 m 2 . The large piston is linked to a small piston of area 144 cm 2 . What is the weight
Question 1. Explain the picture-archiving system used in diagnostic imaging departments. 2. Discuss the role of Medical Imaging Informatics in modern radiology departments.
#questionMnS is a paramagnetic solid. At 300°K, there are 4 × 1022 molecules of MnS per cm3. If the cationic magnetic moment of MnS is 5 MB, use the Curie law in 8-b to compute the
Why does it take longer to heat a bucket of water than a cup of water? Because there is extra water in a bucket than in a cup, and more energy has to be put into the bucket of
Inductors are used extensively in analogue circuits and signal processing. Inductor in conjunction with capacitors and other components form tuned circuits which can emphasize or f
The angular displacement of a body is a function of time and giving by equation h=10+3t+6t square,where t is in seconds.determine the angular velocity, acceleration when t=5seconds
Intensities of an ordinary light and laser light The intensity (I) of a wave is the energy per unit time flowing through a unit normal area. The light from an ordinary light so
the magnetic field at a dictance of 2cm from the axis of a straight conductor carrying current is 12mT.Find the currentin the conductor?
Fig- detremines a square loop Made from a uniform wire. Determine the magnetic field at the centre of the square if a battery is connected among the points A and C.
P1V1/T1=P2V2/T2 BUT TEMP. REMAINS CONSTANT. SO P1V1=P2V2 OR P1V1=P2(V1-V1/10) OR P1V1=P2*9V1/10 OR P1=9P2/10 OR P2=10P1/9 NOW, PERCENTAGE INCREASE=(P2-P1)*100/P1 WHICH IS EQUAL TO 100/9%
P1V1/T1=P2V2/T2
BUT TEMP. REMAINS CONSTANT.
SO P1V1=P2V2
OR P1V1=P2(V1-V1/10)
OR P1V1=P2*9V1/10
OR P1=9P2/10
OR P2=10P1/9
NOW, PERCENTAGE INCREASE=(P2-P1)*100/P1
WHICH IS EQUAL TO 100/9%
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