Calculate heat energy required, Chemistry

Assignment Help:

Calculate how much heat energy is required to raise the temperature of a cube of copper of side 2cm. from 300 to 320k. given: density=8933kg/m cube , atomic weight=63.55, cp=24j/k/mole


Related Discussions:- Calculate heat energy required

Uses of benzaldehyde - aldehydes and ketones, Uses of Benzaldehyde - Aldehy...

Uses of Benzaldehyde - Aldehydes and Ketones Benzaldehyde is used, (a) In perfumery (d) In manufacture of dyes (c) In preparation of benzoic acid, cinnamic acid, cinna

Polymers, any information of polymers

any information of polymers

Organic chemistry, Tiffeneau-Demjanov Rearrangement examples

Tiffeneau-Demjanov Rearrangement examples

Nucleic acids - biomolecules, Nucleic Acids - Biomolecules  In every li...

Nucleic Acids - Biomolecules  In every living molecule there are available in nucleo-proteins that are made up of proteins and natural polymers of great biological significance

Hybrisation, examples of spd arrangement

examples of spd arrangement

Homolysis bond fission or homolytic, Homolysis bond fission or Homolytic ...

Homolysis bond fission or Homolytic (i) In homolysis bond, the covalent bond is broken in such a way that every resulting species gets its own electron. This is apt to the crea

If an electron has spin quantum number, If an electron has spin quantum num...

If an electron has spin quantum number of +1/2  and a magnetic quantum number of -1  , it cannot be presented in an: (1) d -orbital (2) f -orbital (3) p -orbital (4)s-

Platinum crystal structure, 1.  Consider a platinum crystal structure (FCC,...

1.  Consider a platinum crystal structure (FCC, R Pt = .139 nm). a.  Sketch the (100), (110), and (111) planes (including the atoms in the second layer if they can be observed

State about the point imperfection, State about the Point imperfection ...

State about the Point imperfection They are imperfect point-like regions in the crystal. One or two atomic diameters is the typical size of a point imperfection.  A substitu

Anna

3/29/2013 3:56:15 AM

Heat energy required = mcT
mass=d.v=8933 . (.02)^3 = .0712 kg = 71.2 gm
mo of moles =  71.2 / 63.55 = 1.12 moles
c=24 j/k-mole.
T=20
H= (1.12) . 24 . 20
  =537.6 Joules (ANS)

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd