Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
The Neatee Eatee Hamburger Joint specializes in soyabean burgers. Customers arrive according to the following inter - arrival times between 11.00 am and 2.00 pm:
Interval-arrival times [mts] probability
3 0.30
5 0.20
6 0.15
8 0.20
10 0.15
People who want burgers arrive in single or groups [2 or more]. The following distribution of arrivals has been observed:
# of people probability
1 0.40
2 0.30
3 0.20
4 0.10
Each customer orders between 1 or 2 burgers as shown below:
Burger/person probability
1 0.75
2 0.25
Due to fluctuation in burger eating habits, time taken per burger is:
Length of stay [mts] probability
10 0.25
15 0.45
20 0.35
[if a group enters the joint, the time in the system for the group is determined by the longest length of stay for an individual in the group]
Simulate the behavior of the hamburger joint for 10 hours
The proportion of American Express credit-card holders who pay their credit card bill in full each month is 23%; the other 77% make only a partial or no payment. (a) In a random
Systematic Random Sampling This method is generally used in such cases where a complete list of the population is available from which sample has to be selected. Under this
The data le for this assignment is brain-body-wts.txt, which lists the averages brain weights (gm) and body weights (kg) for a number of animal species. Your task is to t an appr
show that (N,/) IS NOT A SEMI GROUP
We are interested in assessing the effects of temperature (low, medium, and high) and technical configuration on the amount of waste output for a manufacturing plant. Suppose that
Let X, Y, and Z refer to the three random variables. It is known that Var(X) = 4, Var(Y) = 9, and Var(Z) = 16. It is further known that E(X) = 1, E(Y) = 2, and E(Z) = 4. Furthermor
in a normal distribution with a mean of 85 and a STD of 5, what is the percentage of scores between 75 and 90?
Replacement times for CD players are normally distributed with a mean of 7.1 years and standard deviation of 1.4years. Find the probability that a randomly selected CD player will
Examples of grouped, simple and frequency distribution data
a b c d e supply p 3 4 6 8 8 20 q 2 6 0 5 8 30 r 7 11 20 40 3 15 s 1 0 9 14 6 13 d 15 3 12 10 20
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd