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Cache controller
The cache controller is the mind of the cache. Its responsibilities include: performing the snarfs and snoops, updating the TRAM and SRAM and implementing the write policy. Also the cache controller is responsible fordetermining if memory request is cacheable and if a request is a cache miss or hit. The cache controller detects cache misses and controls receiving andsending the cells. This device also controls interface. The cache controller have a status register, which may be read by the processor. The bits of the status register can be used to signal to the processor.
The cache controller accepts commands from the processor. Following are the examplesof the commands are
The cache controller will send a cell to request a cache line when a miss occurs. This cell can also flush an existing dirty line. It is expecting cell to be returned containing the data, and the CPU is stalled till such a cell is received.
8237 modes : Intel 8237 can be set to four different type of style of transfer: 1) Single - One transfer at a time, it allow processor access to the bus between transfers
) What is the difference between re-locatable program and re-locatable data?
Hold Response Sequence The HOLD pin is examined at leading edge of each clock pulse. If it is received active line by the processor before T4 of the earlier cycle/during the T1
Code for Reading Flow & Generating LED Output The code starts with the scanning of the PORT 3, for reading the flow status to check for various flow conditions and compare to
I need a text conversion program written in assembly language
Segment Registers The 8086 addresses a segmented memory unlike 8085. The complete 1 megabyte memory, which 8086 is capable to address is divided into 16 logical segments.Thusea
Pin Description of 8086 The microprocessor 8086 is a 16-bit CPU available in 3 clock rates, for example 5, 8 and 10 MHz, packaged in a40 pin CERDIP or plastic package. The 8
Assembly Code for Reading Flow & Generating Serial Output The timer is timer 1 is set for the baud rate 9600, as the crystal used is of 11.0592 Hz. Then the timer 1 is starte
calculate the number of one bits in bx and complement an equal number of least significant bits in ax hint use the xor instruction
Displacement addressing technique
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