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C program to remove vowels in sentence :
void main()
{
char str[100];
int n;
printf("enter string\n");
gets (str);
n=strlen(str);
printf("\n\n\nSentance after Deleting Vowel:\n\n");
for(int i=0;i { if((str[i]!='a')&&(str[i]!='A')&&(str[i]!='e')&&(str[i]!='E')&&(str[i]!='i')&&(str[i]!='I')&&(str[i]!='o')&&(str[i]!='O')&&(str[i]!='u')&&(str[i]!='U')) printf("%c",str[i]); } getch(); }
if((str[i]!='a')&&(str[i]!='A')&&(str[i]!='e')&&(str[i]!='E')&&(str[i]!='i')&&(str[i]!='I')&&(str[i]!='o')&&(str[i]!='O')&&(str[i]!='u')&&(str[i]!='U'))
printf("%c",str[i]);
}
getch();
Of course it is C[i] = A[i] + B[i].It was a typing mistake,never mind. You just understand the concept. 27-1 b. for grain-size=1 n=A.length grain-size=1 r=n for
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